Question

An 85.0 kg fisherman jumps from a dock at a speed of 4.30 m/s onto their 135.0 kg boat. If the boat was at rest to begin but moves with the fisherman after he lands, what is the final speed of the boat and fisherman? (Hint: this is an inelastic “collision”)
m1v1 + m2v2 = (m1+m2)vf

Answer 1

Answer:

Final speed of boat + man is 1.66 m/s

Explanation:

As we know that there is no friction on the system or there is no external force on this system

So here we can use momentum conservation here

$mv = (m + M)v_f$

so we have

m = 85 kg

M = 135 kg

v = 4.30 m/s

now we have

$85 \times 4.30 = (85 + 135) v$

$v = 1.66 m/s$