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olya-2409 [2.1K]
3 years ago
7

An 85.0 kg fisherman jumps from a dock at a speed of 4.30 m/s onto their 135.0 kg boat. If the boat was at rest to begin but mov

es with the fisherman after he lands, what is the final speed of the boat and fisherman? (Hint: this is an inelastic “collision”)
m1v1 + m2v2 = (m1+m2)vf
Physics
1 answer:
jeka943 years ago
4 0

Answer:

Final speed of boat + man is 1.66 m/s

Explanation:

As we know that there is no friction on the system or there is no external force on this system

So here we can use momentum conservation here

mv = (m + M)v_f

so we have

m = 85 kg

M = 135 kg

v = 4.30 m/s

now we have

85 \times 4.30 = (85 + 135) v

v = 1.66 m/s

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