Answer:
the velocity of the bullet-wood system after the collision is 2.48 m/s
Explanation:
Given;
mass of the bullet, m₀ = 20 g = 0.02 kg
velocity of the bullet, v₀ = 250 m/s
mass of the wood, m₁ = 2 kg
velocity of the wood, v₁ = 0
Let the velocity of the bullet-wood system after collision = v
Apply the principle of conservation of linear momentum to calculate the final velocity of the system;
Initial momentum = final momentum
m₀v₀ + m₁v₁ = v(m₀ + m₁)
0.02 x 250 + 2 x 0 = v(2 + 0.02)
5 + 0 = v(2.02)
5 = 2.02v
v = 5/2.02
v = 2.48 m/s
Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s
Answer:
Im gonna say it is answer A:) Hope this helps!
Explanation:
Answer:
124.88 km/h
34.69 m/s
Explanation:
1633.8 km = 1633800 m
13 hours 4 minutes 58 seconds = 13 + 4/60 + 58/3600 = 13.083 hours
13 hours 4 minutes 58 seconds = 13*3600 + 4*60 + 58 = 47098 seconds
So the average speed in km/h is
1633.8 / 13.083 = 124.88 km/h
The average speed in m/s is
1633800 / 47098 = 34.69 m/s
Answer:
Shaft
coiled
generators
Kinetic
Electrical
Explanation:
By using moving shaft and coiled wire together, electric generators create electricity. Electric generators essentially convert kinetic energy (the energy of motion) into electric energy.
Answer:
R = 60 Ω
Explanation:
given,
Potential of the certain device, V = 120 V
current rating of the circuit, I = 20 A
resistance of the device, R = ?
Using Ohm's Law
V = I R
R = 60 Ω
hence, the resistance of the device is equal to 60 Ω
