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Kryger [21]
3 years ago
8

How much gigameters is 93 million miles

Mathematics
1 answer:
lord [1]3 years ago
5 0
The answer should be 149.668992
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Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 10
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Answer:

The function for the outside temperature is represented by T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right], where t is measured in hours.

Step-by-step explanation:

Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:

Amplitude

A = \frac{100\º-70\º}{2}

A = 15\º

Mean temperature

\bar T = \frac{70\º+100\º}{2}

\bar T = 85\º

Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:

T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]

Where:

\bar T - Mean temperature, measured in degrees.

A - Amplitude, measured in degrees.

\tau - Daily period, measured in hours.

t - Time, measured in hours. (where t = 0 corresponds with 5 AM).

If \bar T = 85\º, A = 15\º and \tau = 24\,h, the resulting function for the outside temperature is:

T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]

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