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andrew11 [14]
3 years ago
8

1. What is the SI unit of emf?

Physics
2 answers:
SVEN [57.7K]3 years ago
8 0
VOLT

USE OHMS LAW V=IR

GREAT WORK SO FAR KEEP IT UP TIGER
dedylja [7]3 years ago
6 0
<h3>Answer:</h3>
  1. volt
  2. 11.3 V
<h3>Explanation:</h3>

1. The volt is the derived SI unit for EMF that has been given a special name. It is equivalent to a watt per ampere, where the watt, too, is a derived unit.

___

2. Total circuit resistance is 4.7Ω + 0.3Ω = 5.0Ω, so the circuit current is ...

  (12 V)/(5.0 Ω) = 2.4 A

Then the voltage across the resistor is ...

... (2.4 A)×(4.7 Ω) = 11.28 V ≈ 11.3 V

_____

<em>Comment on Ohm's Law</em>

I've found the attached diagram to be helpful for remembering the relationships involved in Ohms Law. If you cover the letter of the variable you want to find, the other two show you how to find it.

V = I×R

I = V/R

R = V/I

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A small cork with an excess charge of +6.0 μC (1 μC = 10 -6 C) is placed 0.12 m from another cork, which carries a charge of -4.
Alex

Answer:

a.16.125 N b. The force is an attractive force. c. 2.68 × 10¹³ electrons d. 3.75 × 10¹³ electrons

Explanation:

a. What is the magnitude of the electric force between the corks?

The electrostatic force of attraction between the two corks is given by

F = kq₁q₂/r² where k = 9 × 10⁹ Nm²/C², q₁ = +6.0 μC = +6.0 × 10⁻⁶ C, q₂ = -4.3 μC = -4.3 × 10⁻⁶ C and r = distance between the corks = 0.12 m

Substituting the values of the variables into the equation, we have

F = kq₁q₂/r²

F = 9 × 10⁹ Nm²/C² × +6.0 × 10⁻⁶ C × -4.3 × 10⁻⁶ C/(0.12 m)²

= -232.2 × 10⁻³ Nm²/(0.0144 m)²

= -16125 × 10⁻³ N

= -16.125 N

So, the magnitude of the force is 16.125 N

b. Is this force attractive or repulsive?

Since the direction of the force is negative, it is directed towards the positively charged cork, so the force is an attractive force.

c. How many excess electrons are on the negative cork?

Since Q = ne where Q = charge on negative cork = -4.3 μC = -4.3 × 10⁻⁶ C and n = number of excess electrons and e = electron charge = -1.602 × 10⁻¹⁹ C

So n = Q/e = -4.3 × 10⁻⁶ C/-1.602 × 10⁻¹⁹ C = 2.68 × 10¹³ electrons

d. How many electrons has the positive cork lost?

We need to first find the number of excess positive charge n'

Q' = n'q where Q = charge on positive cork = + 6.0 μC = + 6.0 × 10⁻⁶ C and n = number of excess protons and q = proton charge = +1.602 × 10⁻¹⁹ C

So n' = Q'/q = +6.0 × 10⁻⁶ C/+1.602 × 10⁻¹⁹ C = 3.75 × 10¹³ protons

To maintain a positive charge, the number of excess protons equals the number of electrons lost = 3.75 × 10¹³ electrons

4 0
3 years ago
The scientific principle which explains the observation that the amount of heat transfer accompanying a change in one direction
Sphinxa [80]

Answer:

The Law of the Conservation of Energy

Explanation:

The Energy Conservation Act tells us that any form of energy changes from one form to another. And that you can never have a higher amount of energy than you originally got. That is, if you have 100 [J] of energy to be transferred as heat from one medium to another, only 100 [J] can be used to be transferred, no amount greater than this value can be transferred.

The particular study of Energy Transfer in the form of heat is important in sciences such as thermodynamics and heat transfer.

4 0
3 years ago
To do work,the force must be applied over a
pychu [463]
Are there options for this question?
6 0
3 years ago
Read 2 more answers
What kind of energy drives all the processes important to life on earth?
forsale [732]
Solar radiation is the fundamentalenergy driving our climate system, and nearly all climatic and biologicprocesses on Earth are dependent on solar input. Energy from the sun isessential for many processes on Earthincluding warming of the surface, evaporation, photosynthesis and atmospheric circulation.
5 0
4 years ago
In a common but dangerous prank, a chair is pulled away as a person is moving downward to sit on it, causing the victim to land
Delicious77 [7]

Answer:

a) I = 270.18 Kg*m/s

b) F = -3216.42N

Explanation:

a) We know that:

I = P_f -P_i

Where I is the impulse, P_f is the final momentum and P_i the initial momentum.

so:

I = MV_f -MV_i

where M is the mass, V_f is the final velocity and V_i is the initial velocity.

First we have to find the V_i. So, using the conservation of energy.

Mgh = \frac{1}{2}MV_i^2

where g the gravity and h the altitude. Replacing values, we get:

(79kg)(9.8m/s)(0.6m) = \frac{1}{2}(79kg)V_i^2

solving for V_i:

V_i= 3.42 m/s

Now, replacing in the previus equation:

I = MV_f -MV_i

I = (79kg)(0)-(79kg)(3.42m/s)

I = -270.18 Kg*m/s

The impulse is negative becuase it is upward.

b) We know that:

Ft = I

where F is the force, t the time and I the impulse.

so, replacing values and solving for F, we get:

F(0.084s) = -270.18 Kg*m/s

F = -3216.42N

The force is negative becuase it is upward.

8 0
4 years ago
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