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Artist 52 [7]
3 years ago
14

If electrical energy costs 7¢/kW•h, calculate

Physics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

10 minutes =(1/6)th of an hour

cost of running it for an hour = 0.09*7=0.56 c

in 10 min the cost should be (1/6)*0.56c=0.08c

Explanation:

Your scanner power is 15W so, it will consume 15*60=90Wh of electricity in an hour. that is 0.09KWh.  

So, cost of running it for an hour = 0.09*7=0.56 c

Which means that in 10 min the cost should be (1/6)*0.56c=0.08c

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<span>Work is required to pull a nucleon out of an atomic nucleus. It has more mass outside the nucleus.</span>
6 0
3 years ago
Please help on this one?
koban [17]

Using the given equation:

di = 20.0 * 10.0 / 20.0 - 10.0

di = 200/10

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The answer is A.

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3 years ago
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If a 400-mm diameter pipe with a pipe roughness coefficient of 100 flows full of pressurized water with a head loss of 0.4 ft pe
RoseWind [281]

Answer:

Q = 913.9 gpm

Explanation:

The Hazen Williams equation can be written as follows:

P = \frac{4.52\ Q^{1.85}}{C^{1.85}d^{4.87}}

where,

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Q = Flow Rate in gallon/min (gpm) = ?

d = pipe diameter in inches = (400 mm)(0.0393701 in/1 mm) = 15.75 in

C = roughness coefficient = 100

Therefore,

4\ x \ 10^{-4} = \frac{4.52\ Q^{1.85}}{(100)^{1.85}(15.75)^{4.87}}\\\\Q^{1.85} = \frac{4\ x \ 10^{-4}}{1.33\ x\ 10^{-9}} \\\\Q = (300384.75)^\frac{1}{1.85}

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5 0
3 years ago
A company is interested in buying a new machine to replace their outdated equipment. However, before committing to the purchase,
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The mechanical efficiency = actual work / ideal work

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8 0
3 years ago
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A small metal object is tied to the end of a string and whirled round a circular path of radius 30cm. The object makes 20 oscill
LUCKY_DIMON [66]

Answer:

(i) The angular speed of the small metal object is 25.133 rad/s

(ii) The linear speed of the small metal object is 7.54 m/s.

Explanation:

Given;

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number of revolutions, n = 20

time of motion, t = 5 s

(i) The angular speed of the small metal object is calculated as;

\omega = \frac{20 \ rev}{5 \ s} \times \frac{2 \pi \ rad}{1 \ rev} = \frac{40\pi \ rad}{5 \ s} = 8\pi \ rad/s = 25.133 \ rad/s

(ii) The linear speed of the small metal object is calculated as;

v = \omega r\\\\v = 25.133 \ rad/s \ \times \ 0.3 \ m\\\\v = 7.54 \ m/s

6 0
3 years ago
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