Question

Suppose that you wish to construct a simple ac generator having an output of 12 V maximum when rotated at 60 Hz. A uniform magnetic field of 0.050 T is available. If the area of the rotating coil is 100 cm2, how many turns do you need?

Answer 1

Answer:

You need 63.66 turns.

Explanation:

The number of turns of a magnetic field is given by the following formula:

$N = \frac{V}{S*T*2\pi f}$

In which N is the number of turns, V is the maximum output voltage, S is the area of the rotating coil, in square meters and T is the measure of the magnetic field and f is the frequency.

In this problem, we have that:

Suppose that you wish to construct a simple ac generator having an output of 12 V maximum when rotated at 60 Hz. This means that $V = 12$ and $f = 60$.

A uniform magnetic field of 0.050 T is available. This means that $T = 0.050$.

If the area of the rotating coil is 100 cm2, how many turns do you need?

This means that $S = 0.01$m². So:

$N = \frac{V}{S*T*2\pi f}$

$N = \frac{12}{0.01*0.05*120\pi}$

$N = 63.66$

You need 63.66 turns.

Answer 2

Answer:

The number of turns is 64.

Explanation:

Given that,

Magnetic field = 0.050 T

Area of coil = 100 cm²

Frequency = 60 Hz

Output voltage emf= 12 V

We need to calculate the number of turns

Using formula of induced emf

$emf =NAB\omega$

$N=\dfrac{emf}{A\times B\times2\pi f}$

$N=\dfrac{12}{0.01\times0.050\times2\times3.14\times60}$

$N =63.6 = 64\ turns$

Hence, The number of turns is 64.