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bulgar [2K]
3 years ago
7

A function is great to represent the cost per person to attend the school dance. What restrictions would be made to the domain

Mathematics
1 answer:
Cloud [144]3 years ago
8 0

Answer:

(0, ∞)

Step-by-step explanation:

Take a look at "cost per person."  This involves dividing the total paid for admission tickets divided by the number of people attending.  Obviously this function would not be defined for zero attendees or for partial attendees.  Thus, the domain is made up of all integers greater than zero.

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Let T:R²->R² be a linear transformation ,and assume that T (1,2)=(-1,1) and T(1,-1)=(2,3)
zavuch27 [327]

Answer:

(-4,-1)

Step-by-step explanation:

We are given T(1,2)=(-1,1) and T(1,-1)=(2,3) and T is a linear transformation.

This implies for scalars a and b that

T(a(1,2)+b(-1,1))=aT(1,2)+bT(-1,1)

T((a,2a)+(-b,b))=a(-1,1)+b(2,3)

T((a-b,2a+b))=(-a,a)+(2b,3b)

T((a-b,2a+b))=(-a+2b,a+3b)

This means we should be able to solve the system below to find a and b for T(3,3):

a-b=3 and 2a+b=3

Add equations to eliminate b and solve for a:

3a=6

Divide 3 on both sides:

a=2

If a-b=3 and a=2, then b=-1.

Plug in a=2, b=-1:

T((a-b,2a+b))=(-a+2b,a+3b)

T((2--1,2×2+-1)=(-2+2×-1,2+3×-1)

T(3,3)=(-4,-1).

4 0
2 years ago
A soup can will have a radius of 4 cm and a
DENIUS [597]

Answer:

<h3>            It's about 365 cm²</h3>

Step-by-step explanation:

2×πr² + 2πr×h =

= 2×π×4² + 2π×4×10.5 =

= 32π + 84π =

= 116π ≈

≈ 364.42 cm²

5 0
2 years ago
A wooden disk is shaped like a cylinder with a radius of 20.2 millimeters, and a height of 3.9 millimeters. What is the surface
asambeis [7]
The Area is = 3058.78 pir^2
5 0
3 years ago
What is this expression?
Liula [17]

Answer:

2) 4/3

Step-by-step explanation:

(4^-3 * 3^4 * 4^2)/(3^5 * 4^-2)

4^-3 * 3^4 * 4^2 = 4^-1 * 3^4

(4^-1 * 3^4)/(4^-2 * 3^5)

(3^4)/(3^5) = 1/(3^5-4)

(4^(-1))/(4^-2 * 3^(5-4)

(4^-1)/(4^-2 * 3)

4^(-1 - (-2)) / (3)

-1 - (-2) = 1

4/3

4 0
3 years ago
DEAR SIRS AND MISSES, PLEASE HELP ME!
GaryK [48]
Volume of a cone=\pir^2*h/3
\pi*3^2*6/3=56.55

volume fo a sphere = 4/3\pir^3
4/3*pi*1.5^3=14.14

56.55-14.14=42.41
4 0
2 years ago
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