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zimovet [89]
3 years ago
11

Write an equivalent expression for 5+2+2x+2 please help me ​

Mathematics
1 answer:
patriot [66]3 years ago
8 0

Answer:

2x+9

Step-by-step explanation:

You have to combine like terms. 2x stays the same because there are no other like terms, but 5, 2, and 2 can be added together to make 9

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1/X+4 = 5 it is solving rational equations
finlep [7]
X=1
Subtract four so you get 1/x=1
Multiply by x
1x=1
Divide by 1
7 0
3 years ago
How can I solve this
Evgen [1.6K]

Answer:

\frac{a^{5}b }{x^{6} }

Step-by-step explanation:

you just need to forget about 0 because whole equation is raised to 0

and anything raise to 0 is 1

so

\frac{a^{5}b^{4}  }{x^{6}b^{3}  }  law of exponent a^{n} ÷ a^{m} = a^{n-m}

here b^{4} ÷ b^{3} = b^{4-3}

       = b^{1}

so the answer will be

\frac{a^{5}b }{x^{6} }

4 0
3 years ago
a regular hexagon has a perimeter of 150m. Find it's area. leave your answer in simplest radical form
umka21 [38]
37.5 times the square root of 3
5 0
3 years ago
A family is driving 4,608 kilometers from New York to California. It takes the family a total of 48 hours of driving to get to C
hjlf

Answer:

96 km/hr

Step-by-step explanation:

Average number of kilometers per hour = 4,608 km / 48 hours

Average number of kilometers per hour = 96 km/hr

6 0
4 years ago
Read 2 more answers
Determine the values of the constants B and C so that the function given below is differentiable.
laila [671]
For the function to be differentiable, its derivative has to exist everywhere, which means the derivative itself must be continuous. Differentiating gives

f'(x)=\begin{cases}24x^2&\text{for }x1\end{cases}

The question mark is a placeholder, and if the derivative is to be continuous, then the question mark will have the same value as the limit as x\to1 from either side.

\displaystyle\lim_{x\to1^-}f'(x)=\lim_{x\to1}24x^2=24
\displaystyle\lim_{x\to1^+}f'(x)=\lim_{x\to1}B=B

So the derivative will be continuous as long as B=24

For the function to be differentiable everywhere, we need to require that f(x) is itself continuous, which means the following limits should be the same:

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1}8x^3=8
\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1}Bx+C=24+C

24+C=8\implies C=-16

So, the function should be

f(x)=\begin{cases}8x^3&\text{for }x\le1\\24x-16&\text{for }x>1\end{cases}

with derivative

f'(x)=\begin{cases}24x^2&\text{for }x
5 0
4 years ago
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