Explanation:
The height of an object thrown upward from the floor of a canyon 106 ft deep, with an initial velocity of 120 ft per second. The equation is given by :
Since, the depth of the canyon is (-106 feet) and the time taken by the object to rise to the height of the canyon wall is calculated as :
h = 0
On solving the above quadratic equation,
x₁ = 1.023 seconds
and
x₂ = 6.477 seconds
So, the time taken by the object to rise to the height of the canyon wall is 1.023 seconds (ignoring 6.477 seconds). Hence, this is the required solution.
Answer:
Correct answer = (c) 1.0 uF
Explanation:
Capacitors in parallel = C₁ + C₂ + ...... + Cₙ
In this case, there are two capacitors of 0.5 uF
= 0.5uF + 0.5uF
= 1.0uF
Answer:
Work done, W = 141174 Joules
Explanation:
It is given that,
Constant tension acting on the boat, T = F = 465 N
Speed of the boat, v = 4.6 m/s
Time, t = 1.1 min = 66 seconds
Let W is the work done by the tension. It is equal to the product of force and displacement. It is given by :
Since,
W = 141174 Joules
So, the work is done by the tension is 141174 Joules. Hence, this is the required solution.