A car of mass 960.0 kg accelerates away from an intersection on a horizontal road. When the car speed is 51.1 km/hr (14.2 m/s),
1 answer:
Answer:
Explanation:
The power supplied by the engine is given by
P = Fv
where
F is the force applied
v is the velocity of the car
Here we have
P = 3700 W
v = 14.2 m/s
So we can solve the equation to find the average force:
The net force applied on the car is also equal to
F = ma
where
m = 960.0 kg is the mass of the car
a is the acceleration
Re-arranging the equation, we find the acceleration:
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Answer:
Part 1) Time of travel equals 61 seconds
Part 2) Maximum speed equals 39.66 m/s.
Explanation:
The final speed of the train when it completes half of it's journey is given by third equation of kinematics as
where
'v' is the final speed
'u' is initial speed
'a' is acceleration of the body
's' is the distance covered
Applying the given values we get
Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as
Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance
Thus total time of journey equals
Part b)
the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals