Explanation:
<em>We </em><em>know </em><em>that </em><em>metals </em><em>are </em><em>good </em><em>conductor </em><em>of </em><em>heat</em><em>. </em><em>so </em><em>it </em><em>allows </em><em>the </em><em>heat </em><em>to </em><em>flow </em><em>through </em><em>them </em>
<em>.</em><em> </em><em>So </em><em>as </em><em>we </em><em>know </em><em>the </em><em>spoon </em><em>is </em><em>a </em><em>metal </em><em>which </em><em>is </em><em>left </em><em>on </em><em>a </em><em>bowl </em><em>of </em><em>hot </em><em>soup </em><em>allows </em><em>heat </em><em>to </em><em>flow </em><em>through </em><em>it </em><em>easily </em><em>so </em><em>if </em><em>becomes </em><em>warm</em><em>. </em>
Answer:
Homogenous mixture
Explanation:
Homogenous mixtures like ice cream appear to be uniform, and you cannot see their individual components.
I think that the answer might be A) 1.5 L of NH3(g)
Answer:
14.3 g SO₃
Explanation:
2S + 3O₂ → 2SO₃
First, find the limiting reactant. To do that, calculate the mass of oxygen needed to react with all the sulfur.
5.71 g S × (1 mol S / 32 g S) = 0.178 mol S
0.178 mol S × (3 mol O₂ / 2 mol S) = 0.268 mol O₂
0.268 mol O₂ × (32 g O₂ / mol O₂) = 8.57 g O₂
There are 10.0 g of O₂, so there's enough oxygen. The limiting reactant is therefore sulfur.
Use the mass of sulfur to calculate the mass of sulfur trioxide.
5.71 g S × (1 mol S / 32 g S) = 0.178 mol S
0.178 mol S × (2 mol SO₃ / 2 mol S) = 0.178 mol SO₃
0.178 mol SO₃ × (80 g SO₃ / mol SO₃) = 14.3 g SO₃