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Rom4ik [11]
3 years ago
10

The hybrid orbitals used for bonding by the sulfur atom in the sf4 molecule are ________ orbitals.

Chemistry
1 answer:
mote1985 [20]3 years ago
3 0
The hybrid orbitals used for bonding by the sulfur atom in the sf4 molecule are sp^3d orbitals. Hybrid orbitals are the reaction of a model which incorporate atomic orbitals on a single atom in ways that lead to a new set of orbitals that have geometries appropriate.
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Solid sodium azide (NaN3) produces solid sodium and nitrogen gas. How many grams of sodium azide are needed to yield a volume of
ch4aika [34]

Answer:

52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P*V = n*R*T

In this case, the balanced reaction is:

2 NaN₃ → 2 Na + 3 N₂

You know the following about N₂:

  • P= 1.10 atm
  • V= 26.5 L
  • n=?
  • R=0.082057 \frac{atm*L}{mol*K}
  • T= 295 K

Replacing in the equation for ideal gas:

1.10 atm* 26.5 L= n* 0.082057 \frac{atm*L}{mol*K}*295 K

Solving:

n=\frac{1.10 atm*26.5 L}{0.082057 \frac{atm*L}{mol*K} *295K}

n= 1.2 moles

Now, the following rule of three can be applied: if 3 moles of N₂ are produced by stoichiometry of the reaction from 2 moles of NaN₃, 1.2 moles of N₂ are produced from how many moles of NaN₃?

moles of NaN_{3}=\frac{1.2 molesofN_{2} *2 molesofNaN_{3} }{3 molesofN_{2} }

moles of NaN₃= 0.8

Since the molar mass of sodium azide is 65.01 g / mol, then one last rule of three applies: if 1 mol has 65.01 grams of NaN₃, 0.8 mol how much mass does it have?

mass of NaN_{3} =\frac{0.8 mol*65.01 grams}{1 mol}

mass of NaN₃=52.008 grams

<u><em>52.008 grams of sodium azide are needed to yield a volume of 26.5 L of nitrogen gas at a temperature of 295 K and a pressure of 1.10 atmospheres.</em></u>

6 0
3 years ago
Read 2 more answers
A 9-ounce of glass contains 72 milligrams of vitamin
sleet_krkn [62]
Answer: 7.2 ounces


Explanation:



1) Data:

<span>- glass size: 9-ounce
</span><span>
</span><span>- content of vitamin C: 72 milligrams
</span><span>
</span><span>
</span><span>- glasssize: x
</span><span>
</span><span>- content of vitamin C: 60 milligrams
</span><span>
</span><span>
</span><span>2) Proportion
</span><span>
</span><span>
</span><span>9 ounces / 75 mg = x / 60 mg
</span><span>
</span><span>
</span><span>3) Solution:
</span><span>
</span><span>
</span><span>9 ounces × 60 mg = 75 mg × x
</span><span>
</span><span>
</span><span>⇒ x = 9 ounces × 60 mg / 75 mg = 7.2 ounces
</span>
7 0
3 years ago
How many liters of 0.85 M HCl solution would react completely with 3.5 moles Ca(OH)2?
Neporo4naja [7]
I think B but i'm not for sure
4 0
2 years ago
What phenomenon in nature do scientists use to define the length of a meter? Why is this a better definition than “the length of
sergey [27]

Answer:

The natural phenomenon used to describe the length of a meter is the speed of light. The length of a meter is the length a light path travels in 1/(299792458) seconds through a vacuum.

The definition is better due to the uncertainty involved in the use of the length of a standard meter stick because the length of the meter stick could change due to atmospheric conditions from place to place

Explanation:

8 0
3 years ago
harry potter flips a coin (not magical ) 8 times. He gets heads 1 time. What are the odds that his next flip will be heads? A 10
rodikova [14]
C. 50%
Unless the question is saying he only gets heads once, in which case it would be 0%. Or the coin could have 2 heads. Then it would be 100%.
But I'm pretty sure it's 50%.
7 0
2 years ago
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