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Talja [164]
4 years ago
7

Suggest the methods used to separate the following:

Chemistry
1 answer:
MArishka [77]4 years ago
3 0

Answer:

Separation method for various ingredients are

1. Paneer from curdled milk.  - Filtration

2. Chalk powder from water.  - Filtration

3. Sand from salt solution. - Evaporation

4. Saw dust from water.  - Skim off, sieve or filter

5. Tea leaves from brew. - Filtration.

Explanation:

By the help of a muslin cloth the paneer is separated from the curdled milk, the process is called as the filtration. The paneer will remain in the cloth and curdled milk will be removed. Separation of chalk powder from water is very easy by the process of filtration, after the filtration the chalk powder retentate and the filtrate obtained is the water in absence of chalk.  Salt and sand water separation can be done with the help of evaporation. Separation of the saw dust from water takes place by the method of sieving or sedimentation. The tea leaves are separated from brew by filtration.

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One of the intermediates in the synthesis of glycine from ammonia, carbon dioxide, and methane is aminoacetonitrile, C2H4N2.
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Answer:

  • <em>You could expect 3.48 grams of C₂H₄N₂</em>

Explanation:

You must start by stating the chemical equation for the reaction of ammonia, carbon dioxide, and methane to produce aminoaceto nitrile.

1. Word equation:

Ammonia + Carbon dioxide + Methane → Aminoacetonitrile + Water

2. Balanced chemical equation:

       8NH_3+5CO_2+3CH_4\rightarrow 4C_2H_4N_2 +10H_2O

3. Convert the mass of each reactant into number of moles:

<u>Formula:</u>

  • Number of moles = mass in grams/molar mass

<u>2.11g NH₃</u>

  • Number of moles = 2.11g / 17.03g/mol = 0.124 mol NH₃

<u>14.9g CO₂</u>

  • Number of moles = 14.9g/44.01g/mol = 0.339 mol CO₂

<u>1.75g CH₄</u>

  • Number of moles = 1.75g/16.04g/mol = 0.109 mol CH₄

4. Theoretical mol ratio

From the balanced chemical equation, using the coefficientes:

         8molNH_3:5molCO_2:3molCH_4:4molC_2H_4N_2:10molH_2O

5. Limiting reagent

The available amounts of the reactants are:

  • 0.124 mol NH₃
  • 0.339 mol CO₂
  • 0.109 mol CH₄

Fom the theoretical mole ration, to react with 0.124 mol of NH₃ you would need:

  • 0.124molNH₃ × (5molCO₂/8molNH₃) = 0.0775 mol CO₂

Since there are 0.339 moles available, this is in excess.

  • 0.124molNH₃ × (3molCH₄/8molNH₃) =  0.0465mol CO₂

Since there are 0.109 moles available, this is in excess too.

Hence, the limiting reagent is NH₃.

6. Yield

Use the theoretical ratio:

  • 0.124molNH₃ × (4molC₂H₄N₂ / 8molNH₃) = 0.0620 mol C₂H₄N₂

Convert to grams:

  • Mass = number of moles × molar mass
  • 0..0620 mol × 56.068g/mol = 3.48 g of C₂H₄N₂ ← answer

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