Answer:
Sodium hydroxide
Explanation:
Sodium hydroxide ( NaOH ) -
Sodium hydroxide is an inorganic compound , and is also called caustic soda and lye .
It is an ionic compound , which is white in color and is in solid state .
The cation and anion of this salt are the sodium cation Na⁺ and the hydroxide anions OH⁻ .
<u>It is highly basic in nature and is soluble in water , and when left open in air it can readily absorb moisture from the air , to form a hydrated sodium hydroxide .</u>
Answer:
The type of reaction for the following equation is combustion equation.
Explanation:
Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.
The reaction given to us:
When 1 mole of ethane reacts with 7/2 moles of oxygen gas it gives 3 moles of water and 2 moles of carbon dioxide gas.
The type of reaction for the following equation is combustion equation.
Answer:
Cooking with open, exposed flame to prevent build up of CO₂ which will extinguish the fire
Explanation:
In the cooking process whereby food is heated by the combustion of cooking gas as follows;
C₄H₁₀ (g) + (13/2)O₂ → 4CO₂(g) + 5H₂O(g), ΔH = -2658 kJ·mol⁻¹
The product of the combustion must be allowed to escape freely to allow for more reactant molecules of oxygen and butane to effectively combine.
Whereby, the CO₂ is allowed to remain and accumulate at the reaction site, the CO₂ displaces the oxygen and reduces the butane such that as the CO₂ builds up without removal, the CO₂ and butane will left in the mixture while the fire is extinguished.
Answer: 14.625g
Explanation:
No of moles= mass given/molar mass
No of moles given= 0.375mol
Mass is the unknown (?)
Molar mass of K= 39
No of moles = mass given/molar mass
Substitute the values
0.375= mass/39
Cross multiply
Mass = 39×0.375
Mass= 14.625g
The mass is 14.625g
Answer:
Developing the problem
Explanation:
In order to have an experiment or to make the experiment's data useful, you must first find a problem to solve.
