I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
2/8 of an hour is 15,and 2/6 of an hour is 20 minutes. 20-15 is 5 minutes
Answer:
"The quotient of the opposite of a number squared and 3"
Take "the opposite of a number squared" and call it y.
So you get "The quotient of y and 3"
This is y/3.
Now what is y? "The opposite of a number squared"
Take "The opposite of a number" and call it z.
So y is "z squared"
Replacing y, we get z^2 / 3
But what is z? "The opposite of a number"
Call "a number" x.
The opposite of x is -x.
So z is "-x"
Replacing z, we get (-x)^2 / 3
