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serious [3.7K]
3 years ago
5

An ideal gas undergoes isothermal compression from an initial volume of 4.81 m^3 to a final volume of 2.78 m^3. There is 7.25 mo

l of the gas, and its temperature is 23.1°C. (a) How much work is done by the gas? (b) How much energy is transferred as heat between the gas and its environment?
Physics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

a) W = - 9785.03 J

b) 9785.03 J is transferred to the environment.

Explanation:

n = 7.25 mol be the number of moles of the gas, T = 23.1 + 273 = 296.1 K be the temperature of the gas, Vf = 2.78 m^3 be the final volume of the gas, Vi = 4.81 m^3 be the volume of the gas.

a) The work done on compressing the gas is:

W = n×R×T×ln(Vf/Vi)

   = (7.25)×(8.314)×(296.1)×ln(2.78/4.81)

W = - 9785.03 J

Therefore, the work done on compressing the gas is - 9785.03 J.

b) given the internal energy change is ΔEint vanishes when ΔT = 0, the heat transferred to the environment is found by considering the fact that from the first law of thermodynamics, Q = W = -9785.03 J so 9785.03 J is transferred to the environment.

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A tall cylinder contains 30 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
Anastaziya [24]

Answer:

The gauge pressure is  P_g  =  2058 \ P_a

Explanation:

From the question we are told that

       The height of the water contained is  h_w  =  30 \ cm  =  0.3 \ m

        The height of liquid in the cylinder is  h_t  =  40 \ cm  = 0.4 \ m

       

At the bottom of the cylinder the gauge pressure is  mathematically represented as

        P_g  =  P_w + P_o

Where  P_w is the pressure of water which is mathematically represented as

      P_w  =  \rho_w  *  g * h_w

Now  \rho_w is the density of water with a constant values of  \rho_w  = 1000 \ kg /m^3

   substituting values

      P_w  = 1000 *  9.8 *  0.3

     P_w  =  2940 \  Pa

While P_o is the pressure of oil which is mathematically represented as

          P_o  =  \rho_o *  g *  (h_t -h_w )

Where \rho _o is the density of oil with a constant value

         \rho _o  = 900 \ kg / m^3

substituting values

       P_o  =  900 *  9.8 * (0.4 - 0.3)

       P_o  =  882 \ Pa

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6 0
3 years ago
I need help with these Physics problems​
adoni [48]

Answer:

1. 3 m

2. 27 s

Explanation:

1. "A car traveling at +33 m/s sees a red light and has to stop.  If the driver can accelerate at -5.5 m/s², how far does it travel?"

Given:

v₀ = 33 m/s

v = 0 m/s

a = -5.5 m/s²

Unknown: Δx

To determine the equation you need, look for which variable you don't have and aren't solving for.  In this case, we aren't given time and aren't solving for time.  So look for an equation that doesn't have t in it.

Equation: v² = v₀² + 2aΔx

Substitute and solve:

(0 m/s)² = (33 m/s)² + 2(-5.5 m/s²) Δx

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Given:

v₀ = 0 m/s

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Unknown: t

Equation: Δx = v₀ t + ½ a t²

Substitute and solve:

1800 m = (0 m/s) t + ½ (4.8 m/s²) t²

t ≈ 27 s

4 0
3 years ago
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