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Deffense [45]
3 years ago
7

A ship sends a sound wave below it to the ocean floor to see how deep the ocean is at its location. If it takes 5 seconds for th

e sound wave to travel to a depth of 3625 meters and then reflect back to the ship, how fast is the sound wave traveling? Question 15 options: a) 9062.5 m/s b) 1450 m/s c) 725 m/s d) 18,125 m/s
Physics
1 answer:
ryzh [129]3 years ago
5 0

Answer: (b) 1450m/s

Explanation:The time it takes a sound wave to travel to a particular surface is equal to the time it takes to reflect back to its source.

As such, it would take twice as much time to get to the depth travelled for the sound wave to reflect back to the ship(source).

Therefore, since it takes 5seconds for the reflection to get back to the ship.

Then it takes {5/2}seconds ...which is an equivalent of 2.5seconds for the sound to get to the 3625m depth.

Therefore, the speed(velocity) of the sound waves which is a measure of how fast the sound moves is;

Speed(v)= (3625m)/(2.5s)

The speed of the sound wave is therefore equal to 1450m/s.

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3 years ago
Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitt
Tamiku [17]

Answer:

7 m .

Explanation:

For destructive interference

Path difference = odd multiple of λ /2

Wave length of sound from each of  A and B.

= speed / frequency

λ = 334 / 172 = 2 m

λ/2 = 1 m

If I am  1 m away from B , the path difference will be

8 - 1 = 7 m  which is  odd multiple of 1 or λ /2

So path difference becomes odd multiple of  λ /2.

This is the condition of destructive interference.

So one meter is the closest distance which I can remain at so that i can hear destructive interference.

8 0
4 years ago
Read 2 more answers
Which sentence describes Newton's first law?
Marrrta [24]

\Large{\red{\bf{\blue{\dag} Answer:-}}}

Newton's First Law of Motion :

An object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Here this statement is best represented by the statement : <em>Unbalanced forces cause an object to move.</em><em> </em>[ option c ]

<u>More</u><u> to</u><u> know</u><u> </u><u>:</u><u>-</u>

Newton's 3 laws of motion :-

Newton's First Law of Motion :-

It states that an object stays in rest or in uniform motion unless and until compelled by an external unbalanced force . This is also known as " Law of Inertia " .

Ex - (i) We tend to fall backwards while standing in the bus , when it starts suddenly.

(ii) We tend to fall forward while standing in the bus , when it stops suddenly.

Newton's Second Law of Motion :-

It states that the rate of change of momentum is directly proportional to the applied force in the direction of the force . That is ∆p \propto Force .

Ex - (i) When we push car & a truck with same force the car will have Greater acceleration due to less mass . (Imaginary case ).

(ii) We feel easy to push a empty cart than a full cart .

Newton's Third Law of Motion :-

It states that every action has equal and opposite reaction .

Ex - (i) We are able to walk on ground due to Newton's third law of motion .

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8 0
3 years ago
A wheel rotating about a fixed axis has a constant angular acceleration of 4.0 rad/s2. In a 4.0-s interval the wheel turns throu
anastassius [24]

Answer:

a. 3 s.

Explanation:

Given;

angular acceleration of the wheel, α = 4 rad/s²

time of wheel rotation, t = 4 s

angle of rotation, θ = 80 radians

Apply the kinematic equation below,

\theta = \omega_1 t \ + \ \frac{1}{2} \alpha t^2\\\\80 = 4\omega_1 + \frac{1}{2}*4*4^2\\\\80 = 4\omega_1 + 32\\\\ 4\omega_1 = 48\\\\ \omega_1 = \frac{48}{4}\\\\ \omega_1 = 12 \ rad/s

Given initial angular velocity, ω₀ = 0

Apply the kinematic equation below;

\omega_1 = \omega_o + \alpha t_1\\\\12 = 0 + 4t\\\\4t = 12\\\\t = \frac{12}{4}\\\\t = 3 \ s

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8 0
3 years ago
If you jump off a 10 m diving platform, how long will it take you to hit the water?
Vilka [71]

Answer:

<h2>t=1.43 s</h2>

Option A is the correct option.

Solution,

S=10 m

u=0 m/s

a=9.8 m/s^2

Now,

<h3>2s = a {t}^{2}  \\ or \:  {t}^{2}  =  \frac{2 \times 10}{9.8}  \\ or \:  {t}^{2}  =  \frac{20}{9.8}  \\ or \:  {t}^{2}  = 2.04 \\ or \: t =  \sqrt{2.04}  \\ t = 1.43 \: seconds</h3>

hope this helps...

Good luck on your assignment...

8 0
3 years ago
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