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AVprozaik [17]
3 years ago
10

An ice cream cone has a height of 16 centimeters and a diameter of 4 centimeters. What is the volume of ice cream that can be co

ntained within the cone? Use 3.14 for pi.
Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

66.99 cm³

Step-by-step explanation:

V=πr²h /3

V = (3.14)(2)²(16)/3 = 66.99 cm³

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PLS HELP ME I REALLY NEED HELP I DO NOT FEEL GOOD AND I HAVE TO MCUH WORK...pls? (7th grade work)
Murljashka [212]

Answer:

see below

Step-by-step explanation:

65 - 32 = 13

13 divide by 65 = 0.20

0.20 x 100% = 20%

so the percentage drop is 20%

therefore, Marcus is correct.

5 0
4 years ago
5.
puteri [66]
 <span>1C. 5^3 = 125 mL 
2A. 30^3 = 27,000 mL = 27 L 
3D. 75 mm is 7.5 cm, so we do: 7.5^3 = 421.875 mL = 0.421875 L =~ 0.422 L 

Note: 
1 mL = 1 cm^3 
1 L = 1,000 mL 
10 mm = 1 cm</span>
5 0
3 years ago
GEOMETRY-TRIG
Andrej [43]

Answer:

6. The distance Rampy Ronald would have travelled horizontally is approximately 48.428 feet for an actual maximum height of 21.486 feet

7. Rampy Ronald is going to make the jump

Please find attached the graph of the motion of Rampy Ronald, created with Microsoft Excel

Step-by-step explanation:

6. The given parameters are;

The width of the ravine = 80 ft

The inclination of the ramp with which Rampy Ronald will jump = 30°

The distance from the edge of the ravine the ramp ends = 5 feet

The speed with which Rampy Ronald will make the jump = 60 mph

The maximum height he will reach = 30 feet

Therefore, we have;

The height of the end of the ramp = 15 × sin(30°) = 7.5

The height of the end of the ramp = 7.5 feet

The height of the jump = 30 - 7.5 = 22.5

The vertical velocity = 60 × sin(30°) = 30

The vertical velocity = 30 mph

The horizontal velocity = 60 × cos(30°) = 30·√3

The horizontal velocity = 30·√3 mph

From the kinematic equation, v² = u² - 2gh, we have;

u² = 2gh

h = u²/2g = 900/(2 × 32.17405) ≈ 13.986

The maximum height reached 13.986 + 7.5 = 21.486

From v = u - gt

t = u/g = 30/32.17405 ≈ 0.932

t  ≈ 0.932 s

The distance Rampy Ronald would have travelled horizontally = 30·√3 × 0.932 ≈ 48.428

The distance Rampy Ronald would have travelled horizontally ≈ 48.428 feet

7. The time before Rampy Ronald reaches ground level again, is given by the following relation;

h = 1/2·g·t²

21.846 = 1/2 × 32.17405 × t²

t = √(21.846/16.087025) ≈ 1.165

t ≈ 1.366 s

The horizontal distance traveled is therefore;

The horizontal distance traveled from maximum height is 30·√3 × 1.165 ≈ 60.535

The horizontal distance traveled from maximum height is ≈ 70.979 feet

The total horizontal distance traveled ≈ 48.428 + 60.535 = 108.963

The total horizontal distance traveled ≈ 108.963 feet

The total horizontal distance required to make it across the ravine = 5 feet + 80 feet = 85 feet

Therefore, Rampy Ronald is going to make the jump

8 0
3 years ago
The first three steps of completing the square to solve the quadratic equation x^2 +4x-6=0, are shown below
GarryVolchara [31]

Answer: x=sqrt10-2, x=-sqrt10-2

Step-by-step explanation: square root both sides of the equation.

x+2=sqrt10,-sqrt10

subtract 2 from both sides of the equation

x=sqrt10-2, -sqrt10-2

5 0
3 years ago
I need help graphing y equals -4/3 x - 1 o​
lianna [129]

Answer:

Check out my graph!

7 0
3 years ago
Read 2 more answers
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