Not sure exactly what you are asking for
Step-by-step explanation:
But please press make me a brainly
![\bf ~\hspace{10em}1\le x\le 5~\hspace{5em}\sqrt{x^3+36} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \sqrt{x^3+36}\implies \sqrt{x^{2+1}6^2}\implies \sqrt{x^2x6^2}\implies \sqrt{(6x)^2x}\implies 6x\sqrt{x} \\\\\\ \stackrel{\textit{x = 4}}{6(4)\sqrt{4}}\implies 24\sqrt{2^2}\implies 24\cdot 2\implies 48](https://tex.z-dn.net/?f=%5Cbf%20~%5Chspace%7B10em%7D1%5Cle%20x%5Cle%205~%5Chspace%7B5em%7D%5Csqrt%7Bx%5E3%2B36%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Csqrt%7Bx%5E3%2B36%7D%5Cimplies%20%5Csqrt%7Bx%5E%7B2%2B1%7D6%5E2%7D%5Cimplies%20%5Csqrt%7Bx%5E2x6%5E2%7D%5Cimplies%20%5Csqrt%7B%286x%29%5E2x%7D%5Cimplies%206x%5Csqrt%7Bx%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Cstackrel%7B%5Ctextit%7Bx%20%3D%204%7D%7D%7B6%284%29%5Csqrt%7B4%7D%7D%5Cimplies%2024%5Csqrt%7B2%5E2%7D%5Cimplies%2024%5Ccdot%202%5Cimplies%2048)
that's how I read it.... to get some value between 1 and 5, namely 4, to make the expression a rational, well, 48 can be expressed as 48/1.
4 because when you add 2 and 2 it equals 4
Answer:
28 cm
Step-by-step explanation:
If the shape is a square, all the sides are equal. To find the area you multiply the length by the width. Since the area is 49 centimeters, find the square root of 49 to find the length of the length and the height of the square, which is 7. To find perimeter, you add the lengths of all the sides of the square. 7+7+7+7=28.