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siniylev [52]
3 years ago
8

What is the domain of the function y=2sqrtx-6?

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

[6, infinity)

Step-by-step explanation:

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Which graph is the line y=-2/5x+3?
Mashcka [7]
1st we should find the point where the line intersects with the axises 
put x= 0 , so y= 3 ---- > the 1st point (0,3) 
put y=0 , so x = 7.5 ----> the 2nd point (7.5,0) 
so it's the first graph on the left 
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3 years ago
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cricket20 [7]
Since x=-4 and f(x) =x^3 when - 5<=x<=2,
f(-4)= -64

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3 years ago
Twelve pounds of beans are distributed equally into 8 bags to give out at the food bank. How many pounds of beans are in each ba
BaLLatris [955]
There are 1.5 beans in 1 bag
5 0
3 years ago
Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withd
zysi [14]

Answer:

a) $520

b) $580

c) Interest amount is same each year

Step-by-step explanation:

Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.

To find - a) How much money was in the account after one year?

              b) How much money was in the account after 4 years?

              c) Was the amount of money earned in interest the same or different each year?

Proof -

Here given that,

Principal amount = $500

rate of interest = 4% = 4/100 = 0.04

Now,

a)

Amount =  P [ 1 + RT ]

             = 500 [ 1 + 0.04(1)]

             = 500 [ 1 + 0.04] = 520

⇒Amount = $520

b)

Amount =  P [ 1 + RT ]

             = 500 [ 1 + 0.04(4)]

             = 500 [ 1 + 0.16] = 580

⇒Amount = $580

c)

In 2nd year,

Amount =  P [ 1 + RT ]

             = 500 [ 1 + 0.04(2)]

             = 500 [ 1 + 0.08] = 540

⇒Amount = $540

Now,

Interest in 1st year = 520 - 500 = 20

Interest in 2nd year = 540 - 520 = 20

So,

The interest amount  is same each year

3 0
3 years ago
Suppose j varies jointly with g and​ v, and j=2 when g=4 and v=3. <br> Find j when g=8 and v=9.
vladimir2022 [97]

Answer:

j=12

Step-by-step explanation:

we know that

In a join variation, If j varies jointly with respect to g and v, the equation will be of the form j = kgv

where k is a constant

step 1

Find the value of k

we have

j=2,g=4,v=3

substitute and solve for k

2 = k(4)(3)

2 = 12k

k=\frac{1}{6}

The equation is equal to

j=\frac{1}{6}gv

step 2

Find the value of j when g=8,v=9

substitute the values in the equation and solve for j

j=\frac{1}{6}(8)(9)

j=12

3 0
3 years ago
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