Answer:
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
Total outcomes:
100 customers
Desired outcomes:
A clothing vendor estimates that 78 out of every 100 of its online customers do not live within 50 miles of one of its physical stores. So the number of desired outcomes is 78 customers.
Using this estimate, what is the probability that a randomly selected online customer does not live within 50 miles of a physical store?
78% probability that a randomly selected online customer does not live within 50 miles of a physical store.
The first one is 18.5. That was a result of dividing decimals.
Second one is $4.82 because you are trying to find the unit rate.
Third is 2608.75 dollars earned. You multiply the number of memberships with cost, 152. Now you add that with the monthly earnings, resulting in that answer.
Answer: b = 10
Step-by-step explanation:
We want a ratio of b/2 that is equal to the ratio of 1/4 to 1 1/4 (or 5/4).
Ratio of (1/4)/(5/4):
(1/4)/(5/4) = (1/4)*(4/5) = 4/20 = 1/5 or 0.2
We want 2/b = 1/5 or 0.20
2/b = 0.20
b = 2/0.20
b = 10
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Check: Does 10/2 = (1/4)/(5/4)?
Yes
b is 10
Given that Bananas are sold at Php 50 per kilo. The function that describes the situation will be as follows;
The total cost, c, of money required to by b kgs of banas will be given by:
c=50b
This shows that the total cost of a given number of kgs of bananas is given by:
c=50b
