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SIZIF [17.4K]
3 years ago
13

6 < 3x + 9 ≤ 18 please help me I will mark brainiest answer thanks

Mathematics
2 answers:
Olin [163]3 years ago
3 0

Answer:

Step-by-step explanation:

6< 3x + 9

-3x < 9-6

-3x < 3 .( -1 )                                            

3x > 3                          

x > 3/3

x > 3

3x + 9 ≤ 18

3x ≤ 18-9

3x ≤ 9

x ≤ 9/3

x ≤  3

S = {XeIR/ 3 > x  ≤ 3 }

Not sure if the solution looks like this

bearhunter [10]3 years ago
3 0

Answer:

Step-by-step explanation:

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Stels [109]

Answer:

volume = pi r^2 h

or, 190 = pi (3.2)^2 h

or, 190/10.24 = pi h

or, 18.56 = 22/7 h

or, 18.56×7/22 = h

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Answer:

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Given LaTeX: f\left(x\right)=x^{^3}-3x+4f ( x ) = x 3 − 3 x + 4, determine the intervals where the function is increasing and wh
Vedmedyk [2.9K]

Answer:

Increasing: x and x>1.

Decreasing: -1

Step-by-step explanation:

We have been given a function f(x)=x^3-3x+4. We are asked to determine the intervals, where the function is increasing and where it is decreasing.

First of all, we will find critical points of our given function by equating derivative of our given function to 0.

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Now we will take square-root of both sides as:

\sqrt{x^{2}}=\pm\sqrt{1}

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We know that these critical points will divide number line into three intervals. One from negative infinity to -1, 2nd -1 to 1 and 3rd 1 to positive infinity.

Now we will check one number from each interval. If derivative of the point is greater than 0, then function is increasing, if derivative of the point is less than 0, then function is decreasing.

We will check -2 from our 1st interval.

f'(-2)=3(-2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (-\infty, -1) \text{ or } x.

Now we will check 0 for 2nd interval.

f'(0)=3(0)^{2}-3=0-3=-3

Since -3 is less than 0, therefore, function is decreasing on interval (-1,1) \text{ or } -1.

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f'(2)=3(2)^{2}-3=3(4)-3=12-3=9

Since 9 is greater than 0, therefore, function is increasing on interval (1,\infty) \text{ or } x>1.

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Answer:

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Step-by-step explanation:

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We need to check if

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