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Verizon [17]
3 years ago
15

HELLO , PLZ HELP .

Physics
1 answer:
sergey [27]3 years ago
6 0

Answer:

the pressure due to the water on the diver is 200,000 pascal

pressure = height × density × acceleration due to gravity

p = 20×1000×10

p=200,000 pascal

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What are five differences between drama and prose​
Romashka [77]

Answer:

Drama: it has sadness anger and romance

and

i forgot about Prose =w=

Explanation:

6 0
3 years ago
A charged particle is located in an electric field where the magnitude of the electric field strength is 2.0x10^3 newtons per co
Alexxandr [17]

Answer:

20.7

Explanation:

:0 because basis  of the daily occured

6 0
3 years ago
The most energy-efficient way to send a spacecraft to the Moon is to boost its speed while it is in circular orbit about the Ear
jeyben [28]

Answer:

98.33 %

Explanation:

On an elliptical orbit, angular momentum will be conserved .

Angular momentum = I ω = mvR

So mv₁R₁ = mv₂R₂

= v₁R₁ = v₂R₂

where v₁ is velocity and R₁ radius in low orbit (perigee)and v₂ and R₂ is velocity and radius in high orbit ( apogee ).

Here R₁ = Radius of the earth , R₂ is distance between moon and earth.

R₁ / R₂ = 1/60

v₁ /v₂ = R₂ / R₁  = 60

v₂ / v₁ = 1 / 60

1 - (v₂ / v₁ ) = 1 -( 1 / 60)

(v₁ -v₂)/v₁ = ( 60-1 )/60

(v₁ -v₂)/v₁ x 100 = 5900/60 = 98.33 %

5 0
4 years ago
A ball is thrown vertically upward with a speed of 18.0 m/s. (a) How high does it rise? (b) How long does it take to reach its h
Mrrafil [7]

Answer:

a) y=16.53m

b) t_{up}=1.83s

c)t_{down}=1.84s

d) v=-18m/s

Explanation:

a) To find the <u>highest point</u> of the ball we need to know that at that point the ball stops going up and its velocity become 0

v^{2} =v^{2} _{o} +2g(y-y_{o})

0=(18)^{2} -2(9.8)(y-0)

Solving for y

y=\frac{(18)^{2} }{2(9.8)}=16.53m

b) To find how long does it take to reach that point:

v=v_{o}+at

0=18-9.8t

<em><u>Solving for t</u></em>

t_{up} =\frac{18m/s}{9.8m/s^{2} }= 1.83s

c) To find how long does it take to hit the ground after it reaches its highest point we need to find how long does it take to do the whole motion and then subtract the time that takes to go up

y=y_{o}+v_{o}t+\frac{1}{2}gt^{2}

0=0+18t-\frac{1}{2}(9.8)t^{2}

Solving for t

t=0 s <em>or </em>t=3.67s

Since time can not be negative, we choose the second option

t_{down}=t-t_{up}=3.67s-1.83s=1.84s

d) To find the <u><em>velocity</em></u> when it returns to the level from which it started we need to use the following formula:

v=v_{o}+at

v=18m/s-(9.8m/s^{2} )(3.67s)=-18m/s

The sign means the ball is going down

8 0
4 years ago
A 50 kg skydiver is falling downwards and accelerating 6 m/s2 down. What is the net force on the skydiver?
Montano1993 [528]

Net Force = (mass) x (acceleration)  (Newton #2)

Net Force = (50 kg) x (6 m/s² down)

Net Force = (50 * 6) (kg-m/s² down)

<em>Net Force = 300 Newtons down</em>

6 0
3 years ago
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