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Lunna [17]
3 years ago
7

A 2.0 kg puck is at rest on a level table. It is pushed straight north with a constant force of 5N for 1.50 s and then let go. H

ow far does the puck move from rest in 2.25 s?

Physics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

d = 6.32 m

Explanation:

Given that,

The mass of a puck, m = 2 kg

It is pushed straight north with a constant force of 5N for 1.50 s and then let go.

We need to find the distance covered by the puck when move from rest in 2.25 s.

We know that,

F = ma

a=\dfrac{F}{m}\\\\a=\dfrac{5}{2}\\\\a=2.5\ m/s^2

Let d is the distance moved in 2.25 s. Using second equation of motion,

d=ut+\dfrac{1}{2}at^2\\\\d=0+\dfrac{1}{2}\times 2.5\times (2.25)^2\\\\d=6.32\ m

So, it will move 6.32 m from rest in 2.25 seconds.

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Which is a product of photosynthesis? glucose water starch carbon dioxide
nadezda [96]

Glucose, Carbon, water


Hope this helps!

5 0
3 years ago
Read 2 more answers
1. A densidade do nitrogênio nas condições normais de temperatura e pressão é igual a 1,24507 kg/m³. Qual a massa de 200 cm³ de
Levart [38]

Answer:

5.49×10⁻⁴ lbm

Explanation:

Convert volume to m³.

V = (200 cm³) (1 m / 100 cm)³ = 0.0002 m³

Find mass in kg.

m = ρV

m = (1.24507 kg/m³) (0.0002 m³)

m = 0.000249 kg

Convert mass to lbm.

m = (0.000249 kg) (2.205 lbm/kg)

m = 0.000549 lbm

m = 5.49×10⁻⁴ lbm

3 0
3 years ago
Please write a paragraph (5 sentence minimum) that describes convection in Earth's atmosphere.
ExtremeBDS [4]

Answer:

Earth's crust is covered by a densed air blanket called atmosphere. Due to which we feel warm even during night when there is no sun. The air near the atmosphere is less dense compared to the air near our crust. Similarly we can experience high pressure near the atmosphere comparelatively we experience less pressure near crust. The presence of atmosphere above us makes the wind fair sometimes stromy and also helps in pteperation of wind and breezes in earth's surface.

5 0
3 years ago
(ii) Calculate the force required to accelerate a mass of 60 kg at 2.5m/s2<br> force =<br> [2]
ikadub [295]

Answer:

Force = 150 Newton.

Explanation:

Given the following data;

Mass = 60kg

Acceleration = 2.5m/s²

To find the force;

Force = mass * acceleration

Force = 60 * 2.5

Force = 150 Newton.

Therefore, the force required to accelerate this mass is 150 Newton.

7 0
3 years ago
A 20-N falling object encounters 4 N of air resistance. The magnitude of the net force on the object is?
Irina18 [472]

16-N because 20-4=16

8 0
2 years ago
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