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sergeinik [125]
4 years ago
8

Distance between bholu and golu house house 9 km . bholu has to attend golu birthday party at 7am . he started from his home at

6 am on his bicycle and covered a distance of 6 km in 40 mins . At that point he met chintu and he spoke to him for 5 mins and reached goku's birthday party at 7 am . with what speed did he cover the second part of the journey ? calculate his average speed for the entire journey?
Physics
2 answers:
navik [9.2K]4 years ago
6 0
For the rest 3 km


Bholu need to run in 5 minutes so


He need to 3 × 1000 / 5 × 60 m/s

3000/ 300 = 10 m/s


So , his speed should be 1 m/s to reach in 5 minute



mark as brainliest 5 star
bezimeni [28]4 years ago
6 0

Answer:

r mooooommkk/ljjkbtnnnnnbnbvvhhhgggggggjjjjjjjjjjkkjjjkbhbhghghfjhthdrsbrgghbfjkf

Explanation:

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Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m= 60 kg

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The potential energy of the body for each step is;

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P.E = 60 × 9.8 × 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P.E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

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Well, the density of the water is
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Are the two atoms shown below in the image from the same element?
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The answer is yes

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7 0
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A bicyclist is travelling at 25 m/s when he begins to decelerate at -4m/s2 . How fast is travelling after 5 seconds
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Initial velocity (Vi) = 25 m/s

acceleration (a) = -4 m/s^{2}

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Hence, V_{f} = 25 +(-4)(5) = 25 -20 = 5 m/s

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7 0
3 years ago
A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie
ale4655 [162]

Explanation:

It is given that,

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Resistance of the wire, R = 2.4 ohms

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Final magnetic field, B_2=3\ T

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

\epsilon=-A\dfrac{d(B)}{dt}

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7 0
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