Answer:
0.0031 m
Explanation:
y = Length of pixel = 281 μm
L = Distance to screen = 1.3 m
= Wavelength = 550 nm
d = Pupil diameter
= Angle
We have the expression
![tan\theta=\dfrac{y}{L}\\\Rightarrow \theta=tan^{-1}\dfrac{y}{L}\\\Rightarrow \theta=tan^{-1}\dfrac{281\times 10^{-6}}{1.3}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cdfrac%7By%7D%7BL%7D%5C%5C%5CRightarrow%20%5Ctheta%3Dtan%5E%7B-1%7D%5Cdfrac%7By%7D%7BL%7D%5C%5C%5CRightarrow%20%5Ctheta%3Dtan%5E%7B-1%7D%5Cdfrac%7B281%5Ctimes%2010%5E%7B-6%7D%7D%7B1.3%7D)
We have the expression
![sin\theta=1.22\dfrac{\lambda}{d}\\\Rightarrow d=\dfrac{1.22\lambda}{sin\theta}\\\Rightarrow d=\dfrac{1.22\times 550\times 10^{-9}}{sin\left(tan^{-1}\frac{281\times 10^{-6}}{1.3}\right)}\\\Rightarrow d=0.0031\ m](https://tex.z-dn.net/?f=sin%5Ctheta%3D1.22%5Cdfrac%7B%5Clambda%7D%7Bd%7D%5C%5C%5CRightarrow%20d%3D%5Cdfrac%7B1.22%5Clambda%7D%7Bsin%5Ctheta%7D%5C%5C%5CRightarrow%20d%3D%5Cdfrac%7B1.22%5Ctimes%20550%5Ctimes%2010%5E%7B-9%7D%7D%7Bsin%5Cleft%28tan%5E%7B-1%7D%5Cfrac%7B281%5Ctimes%2010%5E%7B-6%7D%7D%7B1.3%7D%5Cright%29%7D%5C%5C%5CRightarrow%20d%3D0.0031%5C%20m)
The pupil diameter is 0.0031 m
Answer:
yes
Explanation:
if friction wasnt there the box just wouldn't of stopped
Answer:
q₁ / q₂ = 4
Explanation:
In this exercise we must use Coulomb's law
F = k q₁q₂ / r²
For this case the electric force is
F = k q₁ Q / r₁²
indicate that another particle q₂ has the same force on Q, but for r₂ = r₁ /2
F = k q₂ Q / r₂²
we equate the two equations
q₁Q / r₁² = q₂ Q / r₂²
we substitute r₂
q₁Q / r₁² = q₂ Q / (r₁/2)²
q₁ = q₂ 4
the relationship between the two charges is
q₁ / q₂ = 4
D.) The energy needed to create work.
Phosphorus, I believe is the answer.