1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
emmasim [6.3K]
3 years ago
7

James has just sold his motorbike for £1,890. He bought the motorbike for £2,700. What fraction of the original cost did he sell

the bike for?
Mathematics
2 answers:
ivanzaharov [21]3 years ago
7 0

Answer: \dfrac{7}{10}

Step-by-step explanation:

Given : James has just sold his motorbike for \pounds1,890.

He bought the motorbike for  \pounds2,700.

Now, the fraction of the original cost for which he sold the bike is given by :-

\dfrac{\text{Selling price}}{\text{Original cost}}\\\\=\dfrac{1890}{2700}\\\\=\dfrac{7}{10}

Hence, the fraction of the original cost for which he sold the bike is \dfrac{7}{10}

valentina_108 [34]3 years ago
3 0
1890/2700=7/10
7/10 is the answer
You might be interested in
3ab+2 x -a =2c a=2 b=3 c=7 True or False
ollegr [7]

Answer:

t

Step-by-step explanation:

8 0
2 years ago
Please help! refer to picture !<br><br>edit: nvm
g100num [7]
Wat??????????????????
7 0
3 years ago
The amounts of money Gillian earned each week from babysitting are $5, 10, $20, $10, $15, $5, $42, $5. How is the mean of the da
Solnce55 [7]

Answer:

The mean will increase, after the outlier is removed.

5 0
3 years ago
If the sphere shown has a radius of 9 units, what is the volume of the sphere?
kirill [66]
V = 4/3 * 3.14 * 9^3 = 3052.08

Answer is B
6 0
3 years ago
Lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. a bank conducts inter
Otrada [13]
Part A:

Given that lie <span>detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector correctly determined that a selected person is saying the truth has a probability of 0.85
Thus p = 0.85

Thus, the probability that </span>the lie detector will conclude that all 15 are telling the truth if <span>all 15 applicants tell the truth is given by:

</span>P(X)={ ^nC_xp^xq^{n-x}} \\  \\ \Rightarrow P(15)={ ^{15}C_{15}(0.85)^{15}(0.15)^0} \\  \\ =1\times0.0874\times1=0.0874
<span>

</span>Part B:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.25
Thus p = 0.15

Thus, the probability that the lie detector will conclude that at least 1 is lying if all 15 applicants tell the truth is given by:

P(X)={ ^nC_xp^xq^{n-x}} \\ \\ \Rightarrow P(X\geq1)=1-P(0) \\  \\ =1-{ ^{15}C_0(0.15)^0(0.85)^{15}} \\ \\ =1-1\times1\times0.0874=1-0.0874 \\  \\ =0.9126


Part C:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The mean is given by:

\mu=npq \\  \\ =15\times0.15\times0.85 \\  \\ =1.9125


Part D:

Given that lie detectors have a 15% chance of concluding that a person is lying even when they are telling the truth. Thus, lie detectors have a 85% chance of concluding that a person is telling the truth when they are indeed telling the truth.

The case that the lie detector wrongly determined that a selected person is lying when the person is actually saying the truth has a probability of 0.15
Thus p = 0.15

The <span>probability that the number of truthful applicants classified as liars is greater than the mean is given by:

</span>P(X\ \textgreater \ \mu)=P(X\ \textgreater \ 1.9125) \\  \\ 1-[P(0)+P(1)]
<span>
</span>P(1)={ ^{15}C_1(0.15)^1(0.85)^{14}} \\  \\ =15\times0.15\times0.1028=0.2312<span>
</span>
8 0
3 years ago
Other questions:
  • What does x equal in 4/5x = 7/5?
    15·2 answers
  • For f(x)=2x − 3 , for what value(s) of x does f(x) = 13?
    14·2 answers
  • What is the distance between ( 0,5 ) , ( -3,-4)​
    7·1 answer
  • List 3 values that would make this inequality true 42 ≤ 24 + y
    15·2 answers
  • Round your answer to the tenths place if necessary<br><br> Help me please! :(
    11·2 answers
  • Evaluate the expression when x = 1/2 and y = -5<br><br> 11x - 8 ( x - y )
    11·1 answer
  • What is the total area? Use 3 for Pi.<br> Answer fast pls!! xx
    5·2 answers
  • 8 meters are in how many feet? Round your answer to the nearest tenth
    15·2 answers
  • Can some one please help me
    15·1 answer
  • Rodea la fracción que sigue y escribe el patrón que corresponde en cada sucesion​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!