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nikdorinn [45]
3 years ago
11

Why does the moon appear to change shape?

Physics
1 answer:
olasank [31]3 years ago
8 0

Answer: The reason the moon appears to change is because

B: It moves closer and farther away from the earth in a yearly pattern.

Explanation: The Moon appears to change shape because we see different amounts of the lit part as the Moon orbits Earth.

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At what point in the cardiac cycle is pressure in the ventricles the highest (around 120 mm Hg in the left ventricle)?
skad [1K]

Answer:

Ventricular systole

Explanation:

This contraction causes an increase in pressure inside the ventricles, being the highest during the entire cardiac cycle. The ejection of blood contained in them takes place. Therefore, blood is prevented from returning to the atria by increasing pressure, which closes the bicuspid and tricuspid valves.

8 0
3 years ago
Is sound potential or kinetic energy
qwelly [4]

Answer:

Sound energy (that is, mechanical vibrational waves passing through an elastic medium) is a combination of kinetic and potential energies. As the wave compresses the medium (storing elastic potential energy) the medium comes to rest (no motion so no kinetic energy).

Explanation:

Hope this helps :D

3 0
3 years ago
A 64.0 kg pole vaulter running at 10.2 m/s vaults over the bar. If the vaulter's horizontal component of velocity over the bar i
Lubov Fominskaja [6]

Answer:

h = 5.05 m

Explanation:

given,

mass of pole vaulter, m = 64 Kg

speed of the vaulter,V = 10.2 m/s

horizontal component of velocity in air, v = 1 m/s

height of the jump,h = ?

using energy conservation

     E_i = E_f

\dfrac{1}{2}mv_i^2 + m g h_i= \dfrac{1}{2}mv_f^2+m g h_f

initial height of the vaulter is equal to zero.

\dfrac{1}{2}v_i^2 = \dfrac{1}{2}v_f^2+gh_f

h =\dfrac{v_i^2-v_f^2}{2g}

h =\dfrac{10^2-1^2}{2\times 9.8}

 h = 5.05 m

height of the jump is equal to 5.05 m.

4 0
4 years ago
CELLS!!
USPshnik [31]

Answer:

A. electromagnetic energy

B. The cell wall and the central vacuole

C. mitochondria

6 0
3 years ago
Read 2 more answers
An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600
arsen [322]

Answer:

A)

8.75\times10^{5} N

B)

1.7\times10^{4} N

Explanation:

d = diameter of the spherical chamber = 5.50 m

Volume of the spherical chamber is given as

V = \frac{4\pi (\frac{d}{2} )^{3}}{3}\\ V = \frac{4(3.14) (\frac{5.50}{2} )^{3}}{3}\\V = 87.07 m^{3}

\rho = density of the seawater = 1025 kg m⁻³

Part A)

Force of buoyancy by seawater on the chamber is given as

F_{b} = \rho V g \\F_{b} = (1025) (87.07) (9.8)\\F_{b} = 8.75\times10^{5} N

Part B)

T = tension force in the cable in upward direction

m = mass of the chamber = 87600 kg

Weight of the chamber is given as

F_{g} = mg \\

Using equilibrium of force in the vertical direction, we have

T + F_{g} = F_{b}\\T + m g = F_{b}\\T + (87600) (9.8) = 8.75\times10^{5}\\T = 16520 N \\T = 1.7\times10^{4} N

3 0
3 years ago
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