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ad-work [718]
4 years ago
5

When you lift a book from the ground to your desk, what kind of work do you do negative or positive by lifting the book what do

you change does the book gain or lose energy what kind of energy
Physics
1 answer:
skelet666 [1.2K]4 years ago
7 0
It would be kinetic energy. Let's say the book is weighs 10 Newtons you need to use a force of 10 Newtons to lift the book. In other words it's positive. As you move the book you're giving it energy. Namely potential energy which will turn to kinetic energy if you let it go. So you're changing it's position and energy.
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What must be true about a surface in order for diffuse reflection to occur?
balu736 [363]

Answer:

carpet

Explanation:

Diffuse reflection is the reflection of light from a surface such that an incident ray is reflected at many angles rather than at just one angle as in the case of specular reflection.

The structure of carpet's surface is as shown. Thus it shows large amount of diffuse reflection.

4 0
3 years ago
An object weighs 32 newtons. What is its mass if a gravitometer indicates that g = 8.25 m/s2?
Nata [24]

Answer:

3.88kg

Explanation:

From the question given, we obtained the following data:

W = 32N

g = 8.25 m/s2

M =?

W = M x g

M = W/g

M = 32/8.25

M = 3.88Kg

The mass of the object is 3.88kg

3 0
4 years ago
Define the unit of current. Name the device which is used to measure
Free_Kalibri [48]

Answer:

The ampere, symbol A, is the SI unit of electric current. It is defined by taking the fixed numerical value of the elementary charge e to be 1.602 176 634 x 10-19 when expressed in the unit C, which is equal to A s, where the second is defined in terms of ΔνCs.

the device used to measure current in a circuit is ammeter

3 0
3 years ago
the resistivity of gold is 2.44×10−8Ω⋅m at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a cur
cricket20 [7]

Answer:

0.03605 V/m is the electric field in the gold wire.

Explanation:

Resistivity of the gold = \rho = 2.44\times 10^{-8} \Omega.m

Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)

Diameter of the wire = d = 0.9 mm

Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm = 0.45\times 0.001 m

( 1mm = 0.001 m)

Area of the cross-section = A=\pi r^2=\pi r^(0.45\times 0.001 m)^2

Resistance of the wire = R

Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)

R=\rho\times \frac{L}{A}

V(voltage)=I(current)\times R(Resistance) ( Ohm's law)

\frac{V}{I}=\rho\times \frac{L}{A}

We know, Electric field is given by :

E=\frac{dV}{dr}

E=\frac{V}{L}

E=\frac{V}{L}=\rho\times \frac{I}{A}

E=2.44\times 10^{-8} \Omega.m\times \frac{0.940 A}{\pi r^(0.45\times 0.001 m)^2}=0.03605 V/m

0.03605 V/m is the electric field in the gold wire.

3 0
4 years ago
Restless tectonic plates move (shift) between one and fifteen centimeters per __________. 1)year 2)month 3)day 4)minute
Alina [70]
1(year is the answer


4 0
3 years ago
Read 2 more answers
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