sin θ = 3 / 7 = .429
sin^2 θ + cos^2 θ = 1 trig identity
9/49 + cos^2 θ = 1
cos^2 θ = 40 / 49 = .816 cos θ = .903
Check .429^2 + .903^2 = 1
cos .903 = 25.4 deg
In the second quadrant sin = +, cos = -, tan = -
So 25.4 deg in the second quadrant = 180 - 25.4 = 154.6 deg
Check:
sin 154.6 = .428
cos 154.6 = -.903
tan 154.6 = -.475
5x -2y = -10 .....1
3x + 6y =66......2
on multiplying eq. 1 by 3
5x -2y = -10 .....1 ×3
15x -6y =-30
now subtract both equations ,
15x -6y =-30
3x + 6y =66
-___-_____-_
12x =-96
x= -8.
putting value of x in eq 1
5×8 -2y =-10
40 -2y =-10
40-10=2y
50=2y
25=y.
The consumption of electricity in May based on the model will be 1225kw.
<h3>How to calculate the consumption?</h3>
The model that's given to calculate the consumption is:
C = 1200 + 5t
May = 5th month
The consumption in May will be:
C = 1200 + 5t
C = 1200 + 5(5)
C = 1200 + 25
C = 1225Kw
In conclusion, the consumption of electricity in May based on the model will be 1225kw.
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Answer:
The answer for this question is Quadrant III
Answer:
Step-by-step explanation:
x+2/x = 3/2
(x + 2)*2 = 3*x {cross multiplication}
2x + 4 =3x
2x-3x = -4
-x = -4
x = 4
