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Anestetic [448]
3 years ago
8

A rocket blasts off from rest and attains a speed of 49 m/s in 14 s. an astronaut has a mass of 54.8 kg. what is the astronaut's

apparent weight during take off?
Physics
1 answer:
emmainna [20.7K]3 years ago
4 0
I am not sure what do ya mean by apparent weight i am quite sure of the solution
acceletarion=( 49-0)/14=3.5m/s^2
weight= 3.5*54.8kg=191.8N
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In a compound, the atom does or does not take on a new set of properties
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It does take on new set of proerties
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Describes the relationship between the spectrum of one atom and the spectrum of another?
krok68 [10]

The relationship between the number of visible spectral lines are identical for atoms .However they have unique wavelengths.

Option B

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6 0
3 years ago
Perform the following calculations and give your answer with the correct number of significant figures
love history [14]

Answer:

see below

Explanation:

a. 0.1886 x 12 =2.2632

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2.3

b. 2.995 - 0.16685 =2.82815

The most accurate in the problem is to thousands place so our answer can only be accurate to the thousands place

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c. 910 x 0.18945=172.3995

The  least number of significant figures is 3 so the answer can only have 3 significant figures

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3 0
3 years ago
You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a c
Sergeeva-Olga [200]

Answer:

Fnet = 0

Explanation:

  • Since the block slides across the floor at constant speed, this means that it's not accelerated.
  • According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.
  • This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:

       F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N  (1)

  • In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:

      F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N  (2)

⇒    169 N + Fn = Fg = 216 N  (3)

  • This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:
  • Fn = 216 N - 169 N = 47  N (4)

6 0
2 years ago
Help with this review pls!!
o-na [289]
40 50 60 85 954 746 ity
5 0
3 years ago
Read 2 more answers
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