Question

A piston in an internal combustion engine applies torque during 150° of each full rotation of the crankshaft to which it is connected. Suppose an 8-cylinder engine (8 such pistons) is running with its crankshaft turning at 2500 rpm and produces 410J of work each second. What is the torque applied to the crank shaft by one of the engine’s eight pistons?

Answer 1

Answer:

T=1.566 N.m

Explanation:

Given that:

rotational speed of the scrank shaft, N = 2500 rpm

power produced by one cylinder, P = 410 W

We know, in case of rotational power:

$P=\frac{2\pi.N.T}{60}$

where: T= torque

Substituting the respective values in the above eq.

$410=\frac{2\pi\times2500\times T}{60}$

$T= \frac{410\times60}{2\pi\times2500}$

T=1.566 N.m is the torque applied by the each piston of the engine.