What are density conversions

Compasses line up with magnetic fields. A compass will line upA. Parallel to magnetic field lines, with the south pole pointing

Olenka [21]

you are welcome i hope god blesses you today

4 0

3 years ago

Read 2 more answers

Some volcanic eruptions are quiet and others are violent what causes this difference?

Step2247 [10]

Volcanoes that produce explosive eruptions tend to have thicker, more viscous magma, and a greater volume of gas. <span>Different types of volcanoes tend to produce different types of eruptions. Shield volcanoes, those with broad, gentle slopes, produce the quietest eruptions. The main difference is the shape of the volcano.
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Hope this helps,

kwrob

7 0

3 years ago

A 620 kg car is traveling at 24 m/s on horizontal ground when it starts up a 30 m high hill. The engine can produce up to 144,00

sweet-ann [11.9K]

Answer:

The kinetic energy of the car at the top of the hill is 140280 Joules.

Explanation:

Mass of the car, m = 620 kg

Speed of the car, v = 24 m/s

Height of the hill, h = 30 m

The engine can produce up to 144,000 J of work during that time, W = 144,000 J

We need to find the kinetic energy of the car at the top of the hill. It can be calculated using conservation of mechanical energy as :

$(mgh+K)-\dfrac{1}{2}mv^2=144000$

$(620\times 9.8\times 30+K)-\dfrac{1}{2}\times 620\times (24)^2=144000$

$620\times9.8\times30+K=322560$

$K=140280\ J$

So, the kinetic energy of the car at the top of the hill is 140280 Joules. Hence, this is the required solution.

7 0

4 years ago

550 nm light passes through a diffraction grating with 3000 lines per centimeter. The screen is 115 cm away from the grating. Wh

Sloan [31]

Answer:

69.7 cm

Explanation:

What is the distance (in cm) between the 2nd order bright fringe and the 2nd dark fringe?

For a diffraction grating, dsinθ = mλ where d = grating spacing = 1/(3000 lines per cm) = 1/3000 × 100 m per line = 1/300000 m = 1/3 × 10⁻⁵ m, m = order of fringe and λ = wavelength of light = 550 nm = 550 × 10⁻⁹ m.

Also, tanθ = x/D where x = distance of nth order fringe from central maximum and D = distance of screen from grating = 115 cm = 1.15 m

Now sinθ = d/mλ, Since θ is small, sinθ ≅ tanθ

So, d/mλ = x/D for a second order bright fringe, m = 2.

So, d/2λ = x/D

x = dD/2λ

So, x =

For a dark fringe, we have

d/(m + 1/2)λ = x'/D where x' is the distance of the fringe from the central maximum.

For a second-order dark fringe, m = 2. So,

d/(2 + 1/2)λ = x'/D

d/(5/2)λ = x'/D

2d/5λ = x'/D

x' = 2dD/5λ

So, the distance (in cm) between the 2nd order bright fringe and the 2nd dark fringe is x" = dD/2λ - 2dD/5λ

x" = dD/10λ

Substituting the values of the variables into the equation, we have

x"= 1/3 × 10⁻⁵ m × 1.15 m/(10 × 550 × 10⁻⁹ m)

x" = 1.15/165 × 10² m

x" = 0.00697 × 10² m

x" = 0.697 m

x" = 69.7 cm

6 0

3 years ago

This same experiment is performed on the international space station. What is the primary issue with performing this experiment

lions [1.4K]

Answer:

Difference in experimental data.

Explanation:

There is difference of experimental value between the experiment that is performed on the earth and on the international space station because presence of gravity. The result of the experiment on the earth is different due to the presence of gravity that contributes in the result of the experiment as compared to international space station where no gravity is present so there is high difference of the numerical value of the result of both experiments of earth and international space station.

5 0

3 years ago