How many milliliters of 0.125 M FeCl3 are needed to react with an excess of Na2S to produce 3.75 g of Fe2S3 if the percent yield
1 answer:
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Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.
Answer 1) σ Bond a : C has O has
.
Explanation : The orbitals of oxygen and carbon which are involved in hybridization to form sigma bonds. This is observed at 'a' position in the citric acid molecule.
Answer 2) π Bond a: C has π orbitals and O also has π orbitals.
Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.
Answer 3) Bond b: O H has only S orbital involved in bonding.
Explanation : The bonding at 'b' position involves oxygen hydrogen atoms in it. It has
hybridized orbitals and S orbital of hydrogen involved in the bonding.
Answer 4) Bond c: C is O is also
Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of hybridized bonds.
Answer 5) Bond d: C atom has C atom has
Explanation : At the position of 'd' the bonding between two carbon atoms is found to be . Therefore, the orbitals that undergo
hybridization are
.
Answer 6) Bond e : C1 containing O
C2 is
Explanation : The carbon atom which contains oxygen along with a double bond has hybridized orbitals involved in the bonding process; whereas the carbon at C2 has
hybridized orbitals involved during the bonding. This is for the 'e' position.
Answer : It takes less amount of heat to metal 1.0 Kg of ice.
Solution :
The process involved in this problem are :
Now we have to calculate the amount of heat released or absorbed in both processes.
<u>For process 1 :</u>
where,
= amount of heat absorbed = ?
m = mass of water or ice = 1.0 Kg
= enthalpy change for fusion =
Now put all the given values in , we get:
<u>For process 2 :</u>
where,
= amount of heat absorbed = ?
m = mass of water = 1.0 Kg
= specific heat of liquid water =
= initial temperature =
= final temperature =
Now put all the given values in , we get:
From this we conclude that, that means it takes less amount of heat to metal 1.0 Kg of ice.
Hence, the it takes less amount of heat to metal 1.0 Kg of ice.