Help answer the questions above

Chemistry

2 answers:

ss7ja [257]3 years ago

5 0

Answer:

See below

Explanation:

The net force was calculated by subtracting the two opposite forces, which were 30 Newtons and 20 Newtons, to get 10 Newtons
They are unbalanced because the person to the right is pulling with a force of 10 Newtons more that the person on the left.
The motion of the treasure chest is to the right by 10 Newtons.

Vote Brainliest, Thx :)

9966 [12]3 years ago

3 0

Answer: i think i have number one (this might be wrong but i tried and its what i got taught)

Explanation:

as you can see the two people are pushing it right but if you pay attention to where the arrows point and the length it shows there is more chance of it moving (on my hand) right as there isn't enough force to move it left and the small arrow underneath the chest is the friction and how much friction it causes

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What mass of sucrose (C12H22O11) should be combined with 546 g of water to make a solution with an osmotic pressure of 8.80 atm

lesya [120]

Answer: The mass of sucrose required is 69.08 g

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 8.80 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (sucrose) = ?

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 564 mL (Density of water = 1 g/mL)

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = Temperature of the solution = 290 K

Putting values in above equation, we get:

$8.80atm=1\times \frac{\text{Mass of sucrose}\times 1000}{342.3\times 546}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 290K\\\\\text{Mass of sucrose}=\frac{8.80\times 342.3\times 546}{1\times 1000\times 0.0821\times 290}=69.08g$