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astra-53 [7]
3 years ago
10

Help answer the questions above

Chemistry
2 answers:
ss7ja [257]3 years ago
5 0

Answer:

See below

Explanation:

  1. The net force was calculated by subtracting the two opposite forces, which were 30 Newtons and 20 Newtons, to get 10 Newtons
  2. They are unbalanced because the person to the right is pulling with a force of 10 Newtons more that the person on the left.
  3. The motion of the treasure chest is to the right by 10 Newtons.

Vote Brainliest, Thx :)

9966 [12]3 years ago
3 0

Answer: i think i have number one (this might be wrong but i tried and its what i got taught)

Explanation:

as you can see the two people are pushing it right but if you pay attention to where the arrows point and the length it shows there is more chance of it moving (on my hand) right as there isn't enough force to move it left and the small arrow underneath the chest is the friction and how much friction it causes

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What is the empirical formula of a compound that contains 6.10 g of hydrogen and 28 g of nitrogen?
Viktor [21]

Answer:

NH₃

Explanation:

mass H = 6.10 grams

mass N = 28.00 grams

mass cpd = (6.10 + 28.00)grams = 34.10 grams

%H/100wt = (6.10/34.10)100% = 17.9% w/w

%N/100wt = (28.00/34.1)100% = 82.1% w/w

%/100wt => grams/100wt => moles => ratio => reduce => emp ratio

%H/100wt = 17.9% w/w => 17.9g => (17.9/1)moles = 17.9 moles H

%N/100wt = 82.1% w/w => 82.1g => (82.1/14)moles = 5.9 moles N

Ratio N:H => 17.9 : 5.9

Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9

=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)

3 0
3 years ago
What is the molarity of a solution that contains 14 moles of solute and 2 liters of solution?
Nata [24]

Answer:

  7 M

Explanation:

The molarity is defined as "moles per liter." Here, it is ...

  (14 moles)/(2 liters) = 7 moles/liter = 7 M

6 0
3 years ago
explain what happens when anhydrous calcium chloride are exposed to the atmosphere for about two days​
PtichkaEL [24]

Answer:

Explanation:

Calcium chloride is <u>deliquescent.</u> If exposed to air, it will absorb sufficient water from the air to allow it to dissolve. After a short while, instead of a white lump, you will have a pool of clear liquid.

5 0
3 years ago
Write Qc for each of the following:(1) Gaseous sulfur tetrafluoride reacts with liquid water to produce gaseous sulfur dioxide a
snow_tiger [21]

Answer : The expression for reaction quotient will be :

(1) Q_c=\frac{[SO_2][HF]^4}{[SF_4]}

(2) Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}

Explanation :

Reaction quotient (Q_c) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

(1) The given balanced chemical reaction is,

SF_4(g)+2H_2O(l)\rightarrow SO_2(g)+4HF(g)

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.  So, the expression for reaction quotient will be :

Q_c=\frac{[SO_2][HF]^4}{[SF_4]}

(2) The given balanced chemical reaction is,

2MoO_2(s)+XeF_2(g)\rightarrow 2MoF(l)+Xe(g)+2O_2(g)[/texIn this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.  So, the expression for reaction quotient will be :[tex]Q_c=\frac{[O_2]^2[Xe]}{[XeF_2]}

7 0
3 years ago
a 25 ml volume of a sodium hydroxide solution requires 19.6 mL of a 0.189 M HCl acid for neutralization. A 10 mL volume of phosp
Drupady [299]

Answer: 0.172 M

Explanation:

a) To calculate theconcentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=0.189M\\V_1=19.6mL\\n_2=1\\M_2=?\\V_2=25mL

Putting values in above equation, we get:

1\times 0.189\times 19.6=1\times M_2\times 25\\\\M_2=0.148

b) To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_3PO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=3\\M_1=?\\V_1=10mL\\n_2=1\\M_2=0.148\\V_2=34.9mL

Putting values in above equation, we get:

3\times M_1\times 10=1\times 0.148\times 34.9\\\\M_1=0.172M

The concentration of the phosphoric acid solution is 1.172 M

3 0
3 years ago
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