The solid state where particles are more compact
Answer:
The answer to your question is below
Explanation:
a) CI Chlorine is located in group VIIA, so its must gain one electron to be stable.
b) Se Selenium is located in group VIA, it must gain 2 electrons to be stable.
c) N Nitrogen is located in group VA, it must gain 3 electrons to be stable.
d) I Iodine is located in group VIIA, so it must gain 1 electron to be stable.
e) S sulfur is located in group VIA, so it must gain 2 electrons to be stable.
The periodic table of the elements are describe the electronic configuration of the elements on which the properties of the elements depends. Among the given groups only metal, non-metal and semi-metal group are the part of periodic table. The metallic property depends upon the binding energy of the electrons with the nucleus. Thus the elements which have the valence electrons more near to the nucleus that is s-block elements are more metallic in nature. On the other hand the elements which have the valence electrons far from the nucleus are more non-metallic in nature like p-block elements. However the binding energy or the attraction of the outermost electrons to the nucleus depends not only its valence electrons position but also some other factors like shielding effect, effective nuclear charge etc.
The elements which are in between the metals and non-metals can be classified as semi-metals.
Although the conductivity of a material is an inherent property of the metals but sometime the nonmetals or semi-metals are also behave like a conductor due to presence of the other elements, thus it cannot be a p[property of the periodic table. Similarly acidity, flammable gases are not part of the periodic table.
Answer: V = 33.9 L
Explanation: We will use Charles Law to solve for the new volume.
Charles Law is expressed in the following formula. Temperatures must be converted in Kelvin.
V1 / T1 = V2 / T2 then derive for V2
V2 = V1 T2 / T1
= 35 L ( 308 K ) / 318 K
= 33.9 L
