First calculate for the molar mass of the given formula unit, CaCO₃. This can be done by adding up the product when the number of atom is multiplied to its individual molar mass as shown below.
molar mass of CaCO₃ = (1 mol Ca)(40 g Ca/mol Ca) + (1 mol C)(12 g of C/1 mol of C) + (3 mols of O)(16 g O/1 mol O) = 100 g/mol of CaCO₃
Then, divide the given amount of substance by the calculated molar mass.
number of moles = (20 g)(1 mol of CaCO₃/100 g)
number of moles = 0.2 moles of CaCO₃
<em>Answer: 0.2 moles</em>
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Explanation:
You only need a 2 at the end In front of the NaCl
2:7 ratio of ethane to O2 = 15:x 9solve for x)
x=52.5 mol O2
Answer:
See explanation
Explanation:
On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.
CO2(g) + H2O(l) -------> H2CO3(aq)
B. The equations that turn sulfur to sulfuric acid are;
S(l) + O2(g) -----> SO2(g)
2SO2(l) + O2(g) -----> 2SO3(g)
SO3(g) + H2SO4(l) -----> H2S2O7(l)
H2S2O7(l) + H2O(l) ----> 2H2SO4(l)
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At pH 6, H^+ concentration = 1 * 10^-6 M
At pH 2, H^+ concentration = 1 * 10^-2 M
Hence;
1 * 10^-2/1 * 10^-6
= 10^4 times more acidic
