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3 years ago

Which statement about the balanced equations for nuclear and chemical changes is correct? (1 point)

Chemistry

2 answers:

Juli2301 [7.4K]3 years ago

4 0

Answer:

last option. A nuclear equation is balanced according to mass number. A chemical equation is balanced according to the total mass before and after the change.

Explanation:

took the test.

iris [78.8K]3 years ago

3 0

The true statement about the balanced equations for nuclear and chemical changes is; both are balanced according to the total mass before and after the change.

A basic law in science is called the law of conservation of mass. Its general statement is that mass can neither be created nor destroyed.

Both in chemical and nuclear changes, mass is involved and in both cases, the law of conservation of mass strictly applies.

This means that for both chemical and nuclear changes; total mass before reaction must be equal to total mass after reaction.

Hence, both reactions are balanced according to the total mass before and after the change.

Learn more: brainly.com/question/22064431

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What is the [oh−] of a solution with ph 5.75

Gekata [30.6K]

[ H₃O⁺] = 10 ^- pH

[ H₃O⁺] = 10 ^ (- 5.75 )

[H₃O⁺] = 1.778x10⁻⁶ M

Kw = [ H₃O⁺] x [ OH⁻]

1x10⁻¹⁴ = 1.778x10⁻⁶ x [OH⁻]

[OH⁻] = 1x10⁻¹⁴ / 1.778x10⁻⁶

[OH⁻] = 5.62x10⁻⁹ M

hope this helps!

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3 years ago

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Which one of the following substances is a liquid fuel used in rocket engines?

uranmaximum [27]

Liquid oxygen can be used as an oxidizer in rocket fuel as one of two propellants needed.

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3 years ago

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The pKa for a weak acid to be used in the buffer should be as close as possible to the desired pH. What if the pKa is not close

nikdorinn [45]

Answer:

When pH = pKa, the ionizable compound in question (either acid or base) will be half protonated and half deprotonated

Explanation:

A convenient way of expressing the relative strength of an acid is by the value of its pKa, which makes it easy to see in small changes in pKa the changes associated with large variations in Ka. Small pKa values are equivalent to large Ka (dissociation constant) values, and as pKa decreases, the strength of the acid increases.

An acid will be stronger the lower its pKa and in a base it happens the other way around, which is stronger the higher its pKa.

Those dissociation constants are not fixed, they depend on other variables. For example, the dissociation constant changes at different temperatures. However, it maintains its value at the same temperature, before changes in the concentration of any of the species or even under the action of a catalyst.

3 0

3 years ago

Which lunar phase will occur about four days after a waxing crescent?

Mamont248 [21]

Answer:3.5 days is awfully precise and waxing gibbous is awfully vague.Let’s just make sure we understand our terminology. Waxing means getting fatter and gibbous means fat. A waxing gibbous moon lasts for approximately 7 days from the first quarter phase right up to the full moon phase.By 3.5 days I’m assuming you mean half a week and simplifying the lunar phases to 28 days exactly.So we have:Day 0 New moon.Day 7 First quarter.Day 14 Full moon.Day 21 Third quarter.Day 28 New Moon.Between day 0 - 7 we have the waxing crescent phase.Between day 7–14 we have the waxing gibbous phase.Between day 14–21 we have the waning gibbous phase.Between day 21–28 we have the waning crescent phase.So 3.5 days from day 7 would take us to day 10.5 which would still leave us in the waxing gibbous phase. 3.5 days after day 10.5 would take us to the full moon or over into the waning gibbous phase since the full moon lasts only an instant.

Explanation:

3 0

2 years ago

An aqueous barium chloride solution was added to a 15.0 mL sample of a sodium sulfate solution according to the reaction below.

Dimas [21]

<h3>Answer:</h3>

0.523 M

<h3>Explanation:</h3>

The reaction between barium chloride and sodium sulfate is given by

BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)

We are given,

Volume of Na₂SO₄ = 15.0 mL

Mass of of solid BaSO₄ = 1.83 g

Required to determine the molarity of Na₂SO₄ solution

we will use the following steps

<h3>Step 1: Determine moles of the solid BaSO₄</h3>

Mass of BaSO₄ = 1.83 g

To get the number of moles we divide mass by the molar mass

Molar mass of BaSO₄ = 233.38 g/mol

Number of moles = 1.83 g ÷ 233.38 g/mol

= 0.00784 moles

<h3>Step 2: Moles of sodium sulfate used </h3>

From the balanced equation for every 1 mole of sodium sulfate used 1 mole of BaSO₄ was produced.

Therefore, the mole ratio of Na₂SO₄ : BaSO₄ is 1 : 1

Hence, moles of Na₂SO₄ will also be 0.00784 moles

<h3>Step 3: Molarity of sodium sulfate solution </h3>

Volume of sodium sulfate = 15.0 mL or 0.015 L

Number of moles = 0.00784 moles

But, molarity = Moles ÷ Volume

= 0.00784 moles ÷ 0.015 L

= 0.5227 M

= 0.523 M

Thus, the molarity of original sodium sulfate is 0.523 M

7 0

3 years ago