Answer:
CE = 17
Step-by-step explanation:
∵ m∠D = 90
∵ DK ⊥ CE
∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK
In the two Δ KDE and KCD:
∵ m∠KDE = m∠KCD
∵ m∠DKE = m∠CKD
∵ DK is a common side
∴ Δ KDE is similar to ΔKCD
∴ 
∵ DE : CD = 5 : 3
∴ 
∴ KD = 5/3 KC
∵ KE = KC + 8
∵ 
∴ 
∴ 
∴ 
∴ 
∴ KC = (8 × 9) ÷ 16 = 4.5
∴ KE = 8 + 4.5 = 12.5
∴ CE = 12.5 + 4.5 = 17
OK, let's try with no figure. We have an isosceles triangle sides s,s, and b.
Opposite b is angle t.
Draw the altitude h to bisect t. We have two right triangles, legs b/2 and h, hypotenuse s. The angle opposite b/2 is t/2 so
sin(t/2) = (b/2)/s = b/2s
So we arrived at the first part,
b = 2s sin(t/2)
The area of a triangle with sides s,s and included angle t is
A = (1/2) s² sin t
Answer:
10/13 ≈ 76.9%
Step-by-step explanation:
P(A∪B) = P(A) +P(B) -P(A∩B)
P(plays basketball ∪ plays baseball)
= P(plays basketball) +P(plays baseball) -P(plays both)
P(plays basketball ∪ plays baseball) = 16/26 +9/26 -5/26 = 20/26 = 10/13
P(plays basketball or baseball) = 10/13 ≈ 76.9%
36 cupcakes if one cup of flour is 6 cupcakes you multiply the amount of flour by 6
