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jekas [21]
3 years ago
14

What is the transformations of f(x)=(x-2)^2-4

Mathematics
1 answer:
prisoha [69]3 years ago
4 0
This is how to solve the problem: "What is the transformations of f(x)=(x-2)^2-4"

Looking at the quadratic equation given,
f(x)  = (x-2)^2 - 4
It's like seeing product of sum and difference of two squares.

(x-2)^2 - 4
[ (x-2) - 2 ] [ (x-2) + 2 ]
[ x - 2 - 2 ] [ x - 2 + 2 ]
[ x - 4 ] [ x ]
[ x^2 - 4x ]

So the final transformation of f(x) = (x-2)^2 -4 is f(x) = (x^2 - 4x). 
In this way, we are able to show how a complicated equation to simple yet equal equation in quadratic form.



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Stephanie is looking into season passes at magic mountain. The basic membership costs $12 monthly and $6 per each visit . The ep
Sphinxa [80]

Answer:

12

Step-by-step explanation:

so its at 12 visits because its their lowest common factor so i think it should be 12

4 0
3 years ago
What is the value of st÷(6r) if r=5, s=32, and t=45
Lana71 [14]
S = 32 and t = 45
 
You replace the letters into numbers...

Since (st) is the same thing as (s × t), it would be 32 × 45, which equals to 1,440.

Then replace the r with 5, so now it's (6 × 5), instead of (6r).

st ÷ (6r) → 1,440 ÷ 30 = 48

Value of st ÷ (6r) = 48
4 0
3 years ago
49 increased by twice a number m<br> W<br> 49(2m)<br> 2m - 49<br> 49 + 2m<br> 2m + 49
Dovator [93]

Answer:

The answer to this question is 49+2m.

4 0
3 years ago
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Vikentia [17]
#1. A- the square would have the greatest perimeter.
4 0
3 years ago
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A pet store contains 35 light green parakeets (14 females and 21 males) and 44 sky blue parakeets (28 females and 16 males). You
snow_tiger [21]
You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB) 

Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)

Req:
- the probability that it is a female (F) or a sky blue (SB)

Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB) 
                 = [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
                 = 53.16 + 55.70 - 35.44
                 = 73.42%

You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%


7 0
3 years ago
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