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Nana76 [90]
4 years ago
7

Rectangle A has side lengths of 6\text{ cm}6 cm6, space, c, m and 3.5\text{ cm}3.5 cm3, point, 5, space, c, m. The side lengths

of rectangle B are proportional to the side lengths of rectangle A. What could be the side lengths of rectangle B? Choose 2 answers: Choose 2 answers: (Choice A) A 3\text{ cm}3 cm3, space, c, m and 1.75\text{ cm}1.75 cm1, point, 75, space, c, m (Choice B) B 5\text{ cm}5 cm5, space, c, m and 2.5\text{ cm}2.5 cm2, point, 5, space, c, m (Choice C) C 7\text{ cm}7 cm7, space, c, m and 7\text{ cm}7 cm7, space, c, m (Choice D) D 12\text{ cm}12 cm12, space, c, m and 5\text{ cm}5 cm5, space, c, m (Choice E) E 5.25\text{ cm}5.25 cm5, point, 25, space, c, m and 9\text{ cm}9 cm9, space, c, m
Physics
2 answers:
VikaD [51]4 years ago
8 0

Answer:

Explanation:

Gotta work on writing the problem, kida hard to read with the coding text.  Anyway, a rectangle with one side  of 6 cm and another  at 3.5 cm, then rectangle B is proportional to that.  Which basically means rectangle B will be multiplied or divided by some number.

To make the concept a little simpler imagine it was a square with sides of length 2.  a proportional square twice as big would have lengths of 4 and half as big would have lengths of 1.

In this case we need measurements where one is 6 multiplied or divided by a number x, and then 3.5 has the same action done on it with the same number.  so again, twice as big would be 12 and 7 while half as big would be 3 and 1.75  anyway, let's look at the options.

A) 3 and 1.75

B) 5 and 2.5

C) 7 and 7

D) 12 and 5

E) 5.25 and 9

Just to have ti written, the original rectangle is 6 by 3.5

So A is obvious since I used it as an example, this is a proportional rectangle half the size of A.

The rest are harder to check except C.  7 and 7 make a square, but we know the side lengths have to be different, so C is easy to tell it's not right.

B we have to check.  Since it's not as obvious as A, we have to check with math more carefully.  What do we have to multiply 6 by to get 5?  Also, you always want to make the largest side of each rectangle proportional to each other.  Anyway, 6 times 5/6 is 5, so for B to be right, 3.5 times 5/6 needs to be equal to 2.5.  Does it?  Nope, its 2.9166 repeating.  So B is not right.

I'm not going to go through so much explanation for the others, if you don't get something let me know.  

D we could also know quickly isn't right since I told you the measurements if the rectangle is changed to one with a side length of 12.  We would need the other to be 7, so 12 and 5 isn't right.

E is our last possibility, since we need to pick two, but let's check anyway.  we need to multiply 6 by 7/8 to get 5.25.  3.5 times 7/8 is 3.0625, so not 9.  Good thing we checked here, because only one answer looks to be right.  Are you sure you put the right numbers?  Or did I misinterpret some?  

maw [93]4 years ago
5 0

Answer:

A and E

Explanation:

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Answer:

1270.64\ \text{J}

Explanation:

m = Mass of object = \dfrac{mg}{g}

mg = Weight of object = 20 N

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

\theta = Angle of slope = 30^{\circ}

f = Force of friction

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The force balance of the system is

\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}

The work done against friction is 1270.64\ \text{J}.

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3 years ago
If a ball rolls off a 4m high table at 7m/s, how long will it take until it hits the floor
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3 0
4 years ago
What is the density of a cube that has a mass of 3.75 g and a volume of 3 mL?
valina [46]

Answer:

\displaystyle \rho=1.25\ g/ml

Explanation:

<u>Density </u>

The density of a substance is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\displaystyle \rho=\frac{m}{V}

The cube has a mass of m=3.75 g and a volume of V=3 ml, thus the density is:

\displaystyle \rho=\frac{3.75\ g}{3\ ml}

\boxed{\displaystyle \rho=1.25\ g/ml}

Since 1 kg=1000 mg and 1 lt = 1000 ml, the density has the same value but with different units:

\displaystyle \rho=1.25\ kg/l

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3 years ago
A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate
yulyashka [42]

Answer:

The work done by the steam is 213 kJ.

Explanation:

Given that,

Mass = 5 kg

Pressure = 150 kPa

Temperature = 200°C

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Using formula of work done

W=Pm\DeltaV

W=Pm(\dfrac{RT_{1}}{P_{atm}}-\dfrac{RT_{2}}{P_{atm}}

W=\dfrac{PmR}{P_{atm}}(T_{2}-T_{1})

Where,R = gas constant

T = temperature

P = pressure

P_{atm}=Atmosphere pressure

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Put the value into the formula

W=\dfrac{150\times10^{3}\times5\times287.05}{1.01\times10^{5}}\times(473-373)

W=213\ kJ

Hence, The work done by the steam is 213 kJ.    

6 0
3 years ago
A litre of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure,if the pressure is made 75 atm then at which temperat
liberstina [14]

Answer:

45000 K .

Explanation:

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A liter of a gas weigh 2 gram at 300 kelvin temperature and 1 atm pressure

We need to find the temperature in which 1 litre of the same gas weigh 1 gram

in pressure 75 atm.

We know, by ideal gas equation :

PV=nRT

Here , n is no of moles , n=\dfrac{Given \ Weight }{Molecular\ Mass}=\dfrac{w}{M}

Putting initial and final values and dividing them :

\dfrac{P_1V_1}{P_2V_2}=\dfrac{\dfrac{w_1}{M}T_1}{\dfrac{w_2}{M}T_2}

\dfrac{1\times 1}{75\times 1}=\dfrac{\dfrac{2}{M}\times 300}{\dfrac{1}{M}\times T_2}\\ \\T_2=45000\ K.

Hence , this is the required solution.

7 0
4 years ago
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