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torisob [31]
3 years ago
15

A woman exerts a constant horizontal force on a large box. as a result, the box moves across a horizontal floor at a constant sp

eed "vo". if the woman suddenly stops applying a horizontal force to the block, then the block will
Physics
2 answers:
erik [133]3 years ago
5 0

The woman is exerting a constant horizontal force on the box, yet it is moving across the floor at a constant speed. That means there is a frictional force on the box equal in magnitude to the applied force and opposite in direction. When the woman stops applying this force, the box will still be subject to the frictional force. It will then decelerate until it stops moving.

Ne4ueva [31]3 years ago
3 0
The block will explode that’s a big woman
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Explanation:

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Just a quick joke but…. Why are apartments called A-P-A-R-T-M-E-N-T-S if they are so close together??????
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1 year ago
A spinning disk is rotating at a rate of 5 rad/s in the positive counterclock-wise direction. If the disk is subjected to an ang
Anit [1.1K]

Answer:

ωf = 13 rad/s

Explanation:

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3 0
3 years ago
The compass of an airplane indicates that it is headed due north and its airspeed indicator shows that it is moving through the
yarga [219]

Answer:

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Explanation:

This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.

Let's take the north direction with the Y axis and the east direction as the X axis

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         Vx = 100 Km / h              wind

a) See the annex

Analytical calculation of the magnitude of the speed and direction of the aircraft

         V² = Vx² + Vy²

         V = √ (240² + 100²)

         V = 260 km/h

Airplane speed relative to the ground is 260 km/h

         Tan θ = Vy / Vx

         tan θ = 100/240

         θ = 22.6º

           

Direction from north to eastb

b) What direction should the pilot have so that the resulting northbound

          Vo = 240 km/h      airplane

          Vox = Vo cos θ

          Voy = Vo sin  θ

          Vx = 100 km / h      wind

To travel north the speeds the x axis (East) must add zero

         Vx -Vox = 0

         Vx = Vox = Vo cos θ

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          θ = cos⁻¹ (100/240)

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North to West Direction

The speed in that case would be

           V² = Vx² + Vy²

To go north we must find Vy

          Vy² = V² - Vx²

          Vy = √( 240² - 100²)

          Vy = 218.2 km / h

8 0
4 years ago
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Answer:

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