Answer:
The distance traveled by the balloon is 10.77 m
Explanation:
velocity of the ball, = 2 m/s south
velocity of the air, = 5 m/s west
To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.
| 2m/s
|
|
↓
5m/s ←------------------
the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.
R² = 5² + 2²
R² = 29
R = √29
R = 5.385 m/s
The distance traveled by the balloon is calculated as;
d = R x t
where;
t is time of the motion = 2 seconds
d = 5.385 x 2
d = 10.77 m
Therefore, the distance traveled by the balloon is 10.77 m.
Answer:
19m/s
22.3 degrees
Explanation:
it is a case aof relative velocity.
the basic for relative velocity vector equation is :
V_b = V_j + V_(b/j)---------------1
V_b: ball velocity relative to ground
V_j : Jaun velocity relative to ground
V_(b/j): ball velocity relative to jaun
<u>reference frame:</u>
<u>We take east and north as +ve x and +ve y </u>
V_(b/j) = V_b - V_j
so for x-axis;
net x-component of V_(b/j) = 12 sin (37) + 0 = 7.22m/s
net y-component of V_(b/j) = 12 cos (37) + 8 = 17.6m/s
magnitude = ((7.22^2)+(17.6^2))^(0.5) = 19 m/s
<em>*direction with respect to Jaun = angle between the vertical (North) and vector </em>V_(b/j)
<em><u>angle = arctan(7.22/17.6) = 22.3 degrees</u></em>
A: Air masses move and meet.
Answer:
Pteropods are little mollusks (related to snails, slugs and squid) that drift around in ocean currents, feeding on nutrient-rich plankton. Their rich diet makes them delicious to many fish. Seals eat many fish, and sharks eat seals and fish, so there it is: not even 6 degrees of shark separation.
Explanation: