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Elis [28]
3 years ago
10

Consider this equation,

Physics
1 answer:
charle [14.2K]3 years ago
7 0

Answer:

V is changing

as \: skater \: moves :  \: there \: is \: displacement \\ from \: third \: equation \: of \: motion \\  {v}^{2}  =  {u}^{2}  + 2as \\  {( \delta \: V})^{2}  = 2as \\ V \:  \alpha  \: s

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Why did Ptolemy and Galileo had different views about the solar system?
iVinArrow [24]
Galileo only saw the system through a scope
5 0
3 years ago
Read 2 more answers
As the water molecules heat up they become more dense and float to the top. True or False
miss Akunina [59]

Answer: False but read why

Heated water molecules expands ( become less dense) but they do float to the top.

8 0
3 years ago
A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
bekas [8.4K]

Answer:

Explanation:

Given that,

Radius r = 15cm = 0.15m

Area of the circular loop can be determined using the formula for area of a circle

A = π r²

A = π × 0.15²

A = 0.0708 m²

Magnetic field B = 1.2T in positive z direction

B = 1.2 •k T.

If loop is remove from the field in the time interval

∆t = 2.3ms = 2.3×10^-3s

We want to find the average EMF and it is given as

ε = —∆Φ/∆t

The final flux is zero

Φf = 0

Where magnetic flux is given as

Φi = BA Cosθ

Where θ=0 since the area and the magnetic field point in the same direction.

Φi = BA Cos0

Φi = BA

Φi = 1.2 × 0.0708

Φi = 0.0848 Vs

Then, ε = —∆Φ/∆t

ε = —(Φf — Φi) / ∆t

ε = —(0-0.0848) / (2.3×10^-3)

ε = 0.0848 / (2.3×10^-3)

ε = 36.88 V

The EMF is 36.88 Volts

6 0
4 years ago
Match each action to its result. The strength of the electromagnet increases. The electromagnet turns off. The poles of the elec
IceJOKER [234]

Answer:

1) The strength of the electromagnet increases   →   Place a magnetic core inside the coil of wire

2) The electromagnet turns off    →    Turn off the battery supply

3) The poles of the electromagnet reverse     →    Change the direction in which the current flows

Explanation:

when current passes through a coil it behaves a an electromagnet.

Magnetic field strength is given by

B = μ N I  

N is no of turns and

I is the current through coil

μ is permeability of the medium or core in the coil.

1). Magnetic core increase permeability μ so it will strengthen magnetic field:

B = <u>μ</u> N I

2). When the battery turns off current becomes zeroi.e I=0

So B = μ N * 0

⇒ B = 0

so electromagnet turns off

3). Direction of magnetic field can be determine by right hand rule, i.e curl the fingers in the direction of current, thumb will point in the direction of north pole.

so changing current direction will change direction of magnetic field.

5 0
3 years ago
A real battery with internal resistance 0.460 Ω and emf 9.00 V is used to charge a 56.0-µF capacitor. A 21.0-Ω resistor is put i
Margaret [11]

Answer: 1.176×10^-3 s

Explanation: The time constant formulae for an RC circuit is given below as

t =RC

Where t = time constant , R = magnitude of resistance = 21 ohms , C = capacitance of capacitor = 56 uf = 56×10^-6 F

t = 56×10^-6 × 21

t = 1176×10^-6

t = 1.176×10^-3 s

4 0
3 years ago
Read 2 more answers
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