1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Studentka2010 [4]
3 years ago
14

Which explains what a velocity time graph would look like with no acceleration?

Physics
2 answers:
ololo11 [35]3 years ago
7 0
Straight line with no slope
Karolina [17]3 years ago
4 0

Answer:

Hey!

Your answer is C!

Explanation:

HOPE THIS HELPS!!

You might be interested in
A car drives on a circular road of radius R. The distance driven by the car is given by = + [where a and b are constants, and t
pishuonlain [190]

Answer:

The question is incomplete, the complete question is "A car drives on a circular road of radius R. The distance driven by the car is given by d(t)= at^3+bt [where a and b are constants, and t in seconds will give d in meters]. In terms of a, b, and R, and when t = 3 seconds, find an expression for the magnitudes of (i) the tangential acceleration aTAN, and (ii) the radial acceleration aRAD3"

answers:

a.18a m/s^{2}

b. a_{rad}=\frac{(27a +b)^{2}}{R}

Explanation:

First let state the mathematical expression for the tangential acceleration and the radial acceleration.

a. tangential acceleration is express as

a_{tan}=\frac{d|v|}{dt} \\

since the distance is expressed as

d=at^{3}+bt

the derivative is the velocity, hence

V(t)=\frac{dd(t)}{dt}\\V(t)=3at^{2}+b\\

hence when we take the drivative of the velocity we arrive at

a_{tan}=\frac{dv(t)}{dt}\\ a_{tan}=6at\\t=3 \\we have \\a_{tan}=18a m/s^2

b. the expression for the radial acceleration is expressed as

a_{rad}=\frac{v^{2}}{r}\\a_{rad}=\frac{(3at^{2} +b)^{2}}{R}\\t=3\\a_{rad}=\frac{(27a +b)^{2}}{R}

4 0
3 years ago
La corriente que fluye por una resistencia es
kirill [66]
Si I think the answer is lster
4 0
3 years ago
No links plz!!
Pavlova-9 [17]

Answer:

Light

Explanation:

The way a concave mirror works is that since it's concave, the light bounces off of each other. a convex mirror, it curved the opposite, and the mirror has no way to bounce off of itself.

6 0
2 years ago
Show your workikkkkkkkk
Svet_ta [14]

Answer:

Explanation:

F = ma

<u>Assuming</u> the 20° is angle θ measured to the horizontal

mgsinθ - μmgcosθ = ma

g(sinθ - μcosθ) = a

at constant velocity, a = 0

g(sinθ - μcosθ) = 0

   sinθ - μcosθ = 0

                 sinθ = μcosθ

μ = sinθ/cosθ

μ = tanθ

μ = tan20

μ = 0.3639702342...

μ = 0.36

6 0
2 years ago
An object with more mass has more kinetic energy than an object with less mass, if both objects are moving ____.
suter [353]

An object with more mass has more kinetic energy than an object with less mass, if both objects are moving at the same speed. <em>(c)</em>

6 0
3 years ago
Read 2 more answers
Other questions:
  • 2. Două surse coerente oscileaza cu frecventa de 1 Hz, iar undele generate de elel se propaga pe suprafața apei cu viteza de 1,
    7·1 answer
  • The generator in a purely inductive AC circuit has an angular frequency of 363 rad/s. If the maximum voltage is 169 V and the in
    7·1 answer
  • Please Help...........................................................
    5·1 answer
  • Can an object be in equilibrium if it is in motion?
    11·1 answer
  • A 24 V battery is connected in series to a resistor of 4 Ω, a resistor of 12 Ω and a resistor of 15 Ω. What is the current in th
    9·1 answer
  • Covalent Bonds usually bond atoms of which type of elements together?
    6·1 answer
  • You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 15.0 m above the ground, it is tr
    7·1 answer
  • A 55 kg person is in a head-on collision. The car's speed at impact is 12 m/s. Estimate the net force on the person if he or she
    12·1 answer
  • Hello people ~
    12·2 answers
  • Which image best represents kinetic energy?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!