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BARSIC [14]
3 years ago
6

You throw a balloon that floats in the air with a velocity of 2 m / s south . If the wind speed is 5 m / s west , how far south

will the balloon travel after 2 seconds ?
Physics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

The distance traveled by the balloon is 10.77 m

Explanation:

velocity of the ball, v_b = 2 m/s south

velocity of the air, v_a = 5 m/s west

To determine the distance the balloon will travel after 2 seconds, first determine the resultant velocity of the balloon.

                                       | 2m/s

                                       |

                                       |

                                      ↓

      5m/s  ←------------------

the two velocities forms a right angled triangle and the resultant will be the hypotenuses side of the triangle.

R² = 5² + 2²

R² = 29

R = √29

R = 5.385 m/s

The distance traveled by the balloon is calculated as;

d = R x t

where;

t is time of the motion = 2 seconds

d = 5.385 x 2

d = 10.77 m

Therefore, the distance traveled by the balloon is 10.77 m.

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maks197457 [2]
In this system we have the conservation of angular momentum: L₁ = L₂
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Therefore, we will have:
m₁ · r₁² · ω₁ = m₂ · r₂² · ω₂

The mass stays constant, therefore it cancels out, and we can solve for ω<span>₂:
</span>ω₂ =  (r₁/ r₂)² · ω<span>₁
     
Since we know that r</span>₁ = 4r<span>₂, we get:
</span>ω₂ =  (4)² · ω<span>₁
     = 16 </span>· ω<span>₁

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3 years ago
In order for work to be done, a force must cause movement true or false
Darya [45]
True! In order for work to be done, a force must cause movement. 
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The lamborghini murcielago can accelerate from 0 to 27.8 m/s (100 km/hr or 62.2 mi/hr) in a time of 3.40 seconds. Determine the
Ostrovityanka [42]

To determine the acceleration of the car, we use equation of motion

v = u +at

Here, v is final velocity of the car, u is the initial velocity of the car, a is the acceleration of the car in time t.

Given, v = 27.8 \ m/s , u=0 because car accelerate from 0 and t = 3.40 s.

Substituting these values in above equation, we get

27.8 \ m/s = 0 +  a \times 3.40 \ s \\\\ a= \frac{27 .8 m/s}{3.40\ s} = 8.17 \ m/s^2

In mi/ h.s,

1 m = 0.000621371 mile.

1 s = (1/3600 ) hour =   0.000277778 hour.

Therefore,

8.17 \ m/s^2 = 18.2757695061 \ mi/h.s (mile \ per \ hour \ second)

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3 years ago
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Examine the image shown here. Bike helmets like this one have padding made of foam under the hard exterior of the plastic. The f
LenKa [72]

The foam decreases the time of impact.

<h3 />

<h3>What is Impulse?</h3>

The Impulse applied to an object causes a change in the momentum of the object. Impulse is the product of force and time of impact.

J = Ft

where;

  • J is the impulse
  • F is the applied force
  • t is the time of impact

The increase in the time of impact increases the impulse experienced by the object, and a decrease in the time of impact causes a decrease in the impulse experienced by the object.

Thus, we can conclude that the foam decreases the time of impact because it cushions the effect of impact.

Learn more about impulse here: brainly.com/question/25700778

8 0
2 years ago
A 1-kg book is at rest on a desk. Determine the force the desk exerts on the book<br>​
Katena32 [7]
<h3>Answer:</h3>

\displaystyle F_n = 9.8 \ N

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Physics</u>

<u>Forces</u>

SI Unit: Newtons N

Free Body Diagrams

Gravitational Force: \displaystyle F_g = mg

  • m is mass (in kg)
  • g is Earth's gravity (<em>9.8 m/s²</em>)

Normal Force: \displaystyle F_n

Newton's Law of Motions

  1. Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion
  2. Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)
  3. Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1 kg book at <em>rest</em>

<u>Step 2: FBD</u>

<em>See Attachment</em>

<em>Draw a free body diagram to label the forces acting upon the book. We see that we would have gravitational force from Earth pointing downwards and normal force from the surface of the desk pointing upwards.</em>

<em>Since the book is not moving, we know that ∑F = 0 (sum of forces equal to 0).</em>

<u>Step 4: Find Normal Force</u>

  1. Define Forces [Newton's Law of Motions]:                                                 \displaystyle \sum F = 0
  2. [Newton's Law of Motions] Substitute in forces:                                         \displaystyle F_g - F_n = 0
  3. [Newton's Law of Motions] [Addition Property of Equality] Isolate \displaystyle F_n:     \displaystyle F_g = F_n
  4. [Newton's Law of Motions] Substitute in \displaystyle F_g:                                               \displaystyle mg = F_n
  5. [Newton's Law of Motions] Rewrite:                                                             \displaystyle F_n = mg
  6. [Newton's Law of Motions] Substitute in variables:                                   \displaystyle F_n = (1 \ kg)(9.8 \ \frac{m}{s^2})
  7. [Newton's Law of Motions] Multiply:                                                             \displaystyle F_n = 9.8 \ N

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