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Anon25 [30]
3 years ago
13

a person whose mass is 72 kg has a momentum of 700 kg/m/s (E) .What velocity must this person be travelling at?(2 sig figs)

Physics
1 answer:
liberstina [14]3 years ago
7 0
From the information given, the mass of the moving body, which in this case is a person, is 72 kg and the momentum 700 kg m/s. we use the formula p = m × v. Where p is momentum, m is the mass and v is the velocity. We need v so we rewrite the equation thus: v = p/m In our case p = 700 and m = 72 v = p/m → v = 700/ 72 → v = 9.72 Therefore the person is travelling at 9.72 m/s
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By what factor is the intensity of sound at a rock concert louder than that of a whisper when the two intensity levels are 120 d
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Answer:

The intensity of sound at rock concert is  10¹⁰ greater than that of a whisper.

Explanation:

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120 = 10Log(\frac{I}{1*10^{-12}} )\\\\12 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{12}\\\\I = 1*10^{-12} *10^{12}\\\\I = 1*10^0\\\\I =1 \ W/m^2

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20 = 10Log(\frac{I}{1*10^{-12}} )\\\\2 = Log(\frac{I}{1*10^{-12}} )\\\\\frac{I}{1*10^{-12}} = 10^{2}\\\\I = 1*10^{-12} *10^{2}\\\\I = 1*10^{-10}\\\\I =10^{-10} \ W/m^2

Thus, the intensity of sound at rock concert is  10¹⁰ greater than that of a whisper.

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