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nalin [4]
2 years ago
12

You have 50L of water, it froze. So find its new volume. Density of water is 1000kg/m^3 or 1kg/L, density of ice is 920kg/m^3 or

0.92kg/L.
Physics
1 answer:
ad-work [718]2 years ago
4 0

Answer:

D (density) = Mass / Volume

V (ice) = Mass / Density = 50000 g / .92 kg / L

V = 50 kg / .92 kg / L  

1 Liter of water weighs 1 kilogram = 50 L weighs 50000 g

V = 54.3 L     the mass does not change upon the change of phase (freezing)

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What is the definition of energy in scientific terms?.
stepladder [879]

Answer:

energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms.

8 0
2 years ago
A hot iron horseshoe (mass = 0.35 kg ), just forged, is dropped into 1.40 L of water in a 0.45 kg iron pot initially at 22.0°C.
olga_2 [115]

Answer:

420 °C

Explanation:

m_{h} = mass of the horseshoe = 0.35 kg

m_{w} = mass of the water = 1.40 L = 1.40 kg

m_{i} = mass of the iron pot = 0.45 kg

c_{i} = specific heat of iron = 450 J kg⁻¹ °C⁻¹

c_{w} = specific heat of water = 4186 J kg⁻¹ °C⁻¹

T_{hi} = initial temperature of the horseshoe = ?

T_{wi} = initial temperature of the water = 22 °C

T_{pi} = initial temperature of the iron pot = 22 °C

T_{f} = final temperature = 32 °C

Using conservation of Heat

m_{h}c_{i}(T_{hi} - T_{f}) = m_{w}c_{w}(T_{f} - T_{wi}) + m_{i}c_{i}(T_{f} - T_{pi})

(0.35)(450)(T_{hi} - 32) = (1.40)(4186)(32 - 22) + (0.45)(450)(32 - 22)

(157.5)(T_{hi} - 32) = 60629

T_{hi} - 32 = 384.95

T_{hi} = 420 °C

7 0
3 years ago
A swimming pool, 20.0 m ? 12.5 m, is filled with water to a depth of 3.71 m. if the initial temperature of the water is 18.5°c,
Semenov [28]
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7 0
3 years ago
Look around the room you are in. Name
kozerog [31]

Answer:

A wire,rubber

Explanation:

yes

3 0
3 years ago
Read 2 more answers
Hii! help asap. i’ll give brainliest thanks!
o-na [289]

I believe it’s the mass of the box but I don’t no if I’m right

Hope this helped
5 0
2 years ago
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