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kupik [55]
3 years ago
13

Where are the life forms of the biosphere located

Physics
1 answer:
bulgar [2K]3 years ago
7 0
<span>The life forms of the biosphere are located within Earth's surface.</span>
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A certain dielectric with a dielectric constant = 24 can withstand an electric field of 4 107 V/m. Suppose we want to use this d
mr_godi [17]

Answer:

Explanation:

Electric field E = 4 x 10⁷ V / m

Dielectric constant k = 24

capacitance of capacitor

C = kε₀ A / d

d = plate separation

A =  plate area

C = .89 x 10⁻⁶

V / d = electric field

for minimum d , electric field will be maximum

V / d  = 4 x 10⁷

1930 / d = 4 x 10⁷

d = 1930 / 4 x 10⁷

d = 482.5 x 10⁻⁷ m

= 48.25 x 10⁻⁶ m

C = kε₀ A / d

.89 x 10⁻⁶ = 24 ε₀ A / d

A = .89 x 10⁻⁶  X d /  24 ε₀

A = .89 x 10⁻⁶  X 48.25 x 10⁻⁶  /  24  x 8.85 x 10⁻¹²

= 42.9 / 212.4

= .2019 m²

8 0
3 years ago
Read 2 more answers
Two objects are placed 3 meters apart. If they were moved, at what distance would the NEW gravitational force be about 1/4 of th
gayaneshka [121]

Answer:

3/4

Explanation:

3 0
3 years ago
A 4.0-n puck is traveling at 3.0 m/s. it strikes an 8.0-n puck, which is stationary. the two pucks stick together. their common
Natalka [10]
<span>1.0 m/s Momentum = mass x velocity Total Momentum before any collision = total momentum afterwards 4.0 x 3.0= 12 :g x momentum before (x g because using weight) Afterwards, if the velocity of the two joined is v then we get: 'momentum x g'=12v so 12v=12 so v=1m/s</span>
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3 years ago
Two Polaroids are aligned so that the initially unpolarized light passing through them is a maximum. At what angle should one of
steposvetlana [31]

To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.

Mathematically the expression is given as

I = I_0 cos^2\theta

Where,

I_0= Initial Intensity

I = Final Intensity after pass through the polarizer

\theta= Angle between the polarizer and the light

Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as

\frac{I}{I_0} = \frac{1}{2}

Using the Malus Law we have,

I = I_0 cos^2\theta

cos^2\theta = \frac{I}{I_0}

cos^2\theta = \frac{1}{2}

\theta = cos^{-1}(\frac{1}{2})^2

\theta = 75.52\°

Angle with respect to maximum is 90-75.52 = 14.48\°

8 0
3 years ago
G to ml,density=3.291 g/ml
olya-2409 [2.1K]
The density value 3.291 g/ml (gram / milliliter) in words is "three point two nine one g/ml (gram / milliliter)".
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7 0
3 years ago
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