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Free_Kalibri [48]
3 years ago
11

Solve the following system equations:

Mathematics
2 answers:
azamat3 years ago
7 0
(1).. 2x + 4y - 3z = -7 
<span>(2).. 3x + 1y + 4z = -12 </span>
<span>(3).. 1x + 3y + 4z = 4 </span>

<span>****************** </span>
<span>ok.. we're going to put this into matrix form.. where we drop x, y, and z </span>
<span>2.. 4.. -3.. | ... -7 </span>
<span>3.. 1.. .4.. | ... -12 </span>
<span>1.. 3.. .4 . | ... 4 </span>
<span>ok? </span>

<span>now.. I'll designate the rows (1), (2), (3).. ok? </span>
<span>new (1) = -2x(3) + (1) </span>
<span>new (2) = -3x(3) + (2) </span>
<span>ie... </span>
<span>0..-2..-11. | .. -15 </span>
<span>0..-8.. -8.. | ... -24 </span>
<span>1.. 3.. .4 . | ... .+4 </span>

<span>new row (2) = old (2) / -8 </span>
<span>0..-2..-11. | .. -15 </span>
<span>0.. 1.. 1.. | ... +3 </span>
<span>1.. 3.. .4 . | ... +4 </span>

<span>new (1) = 2xold(2) + 1 </span>
<span>new (3) = -3xold(2) + 3 </span>
<span>0.. 0..-9 .. | ... -9 </span>
<span>0.. 1.. 1.. | ... +3 </span>
<span>1.. 0.. .1 . | ... -5 </span>

<span>new row(1) = old row 1 /-9 </span>
<span>0.. 0.. .1 .. | ... +1 </span>
<span>0.. 1.. 1.. | ... +3 </span>
<span>1.. 0.. .1 . | ... -5 </span>

<span>new (2) = old(2) - old(1) </span>
<span>new (3) = old(3) - old(1) </span>
<span>0.. 0.. .1 .. | ... +1 </span>
<span>0.. 1.. 0.. | ... +2 </span>
<span>1.. 0.. .0 . | ... -6 </span>

<span>so.. (x,y,z) = (-6, +2, +1)..
 
the last answer is correct </span>
adell [148]3 years ago
3 0

Answer:

The solution is (–6, 2, 1). (Option A)

Step-by-step explanation:

Given three equations

2x + 4y - 3z = -7  →   (1)

3x + y + 4z = -12  →   (2)

x + 3y + 4z = 4    →   (3)

we have to find the solution of above equations.

By elimination method

Multiply equation (2) by 4 and then subtracting from (1), we get

(2x + 4y - 3z+7)-4(3x + y + 4z + 12)=0

  ⇒  -10x-19z=41 → (4)

Multiply equation (2) by 3 and then subtracting from (3), we get

(x + 3y + 4z - 4)-3(3x + y + 4z + 12)=0

  ⇒ -8x-8z=40 ⇒ x+z=-5 → (5)

Solving (4) and (5), we get

-10x-19z-41+10(x+z+5)=0

 ⇒ -9z=-9 ⇒ z=1

⇒ x+1=-5 ⇒ x=-6

and (3) implies -6 + 3y + 4 = 4 ⇒ y=2

Hence, the solution of above 3 equations will be (x,y,z)=(-6,2,1)

Hence, option (1) is correct.

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17. The distance between (2, 1) and (n, 4) is 5 units. Find all possible values of n.
Rufina [12.5K]

Answer:

6=n   and -2=n

Step-by-step explanation:

The distance between two points is found by

d = sqrt(( x2-x1)^2 + (y2-y1)^2)

5 = sqrt(( n-2)^2 + (4-1)^2)

5 = sqrt(( n-2)^2 + (3)^2)

Square each side

5^2 = sqrt(( n-2)^2 + (3)^2)^2

25 = ( n-2)^2 + (3)^2

25 = (n-2)^2 +9

Subtract 9 from each side

25-9 = (n-2)^2 +9-9

16 = (n-2)^2

Take the square root of each side

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5 0
4 years ago
You are studying 112 returning combat veterans with deployment related injuries. You are testing a cognitive impairment screen t
svlad2 [7]

Answer:

0.9894 = 98.94% probability that he does not have a TBI.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Negative screen

Event B: Does not have a TBI.

Probability of a negative screen:

93 are negative and do not have a TBI.

1 is negative and has a TBI.

Out of 112.

So

P(A) = \frac{93+1}{112} = \frac{94}{112}

Probability of a negative screen and not having a TBI:

93 are negative and do not have a TBI, out of 112, so:

P(A \cap B) = \frac{93}{112}

One of the veterans has a negative screen and wants to know the probability that he does not have a TBI.

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{93}{112}}{\frac{94}{112}} = \frac{93}{94} = 0.9894

0.9894 = 98.94% probability that he does not have a TBI.

6 0
3 years ago
What is the distance between the two points located at (9, 12) and (9, −11)?
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Answer:

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Because the X value in each coordinate point is the same, we only need to subtract the the Y values to find the distance.

12 - (-11) = 23

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