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AlexFokin [52]
3 years ago
6

15:59:26

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0

Answer:

D

Step-by-step explanation: I just took the quiz.

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a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the
Montano1993 [528]
When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}
x=\frac{-25+/-\frac{625+192}}{-32}
x=\frac{-25+/-\frac{817}}{-32}
it has to be a positive time

so it will hit the ground after \frac{25+\sqrt{817}}{32} seconds
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