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bija089 [108]
2 years ago
12

Solve for x. Round your answer to the nearest tenth. Will brainlist first correct

Mathematics
2 answers:
Eduardwww [97]2 years ago
7 0

Answer:

<em>m ∠ CDB ≈ 68.7°</em>

Step-by-step explanation:

Alexxx [7]2 years ago
6 0

the answer to your question is D

You might be interested in
VEEL
Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
3 years ago
Convince me why points B&amp;C are solutions to this system of linear inequalities.
muminat
The coordinates of B and C are solutions to the system of inequalities because both are true to the two inequalities. A is not a solution to the system of inequalities because it is only true to “y is less than or equal to 2x”.
3 0
2 years ago
Solve each system using SUBSTITUTION. Remember to check!
Annette [7]

Answer:

\left \{ {{x=3} \atop {y=-7}} \right.

Step-by-step explanation:

We can directly substitute y of the first equation to the second equation.

-2x - 1 = 3x - 16

5x = 15

x = 3

Substituting back to any of the two equations, we get y = -2(3)-1 = -7.  If you check with the second equation, y = 3(3)-16 = -7 as well.

Therefore \left \{ {{x=3} \atop {y=-7}} \right..

7 0
2 years ago
3(7+x to the power of two);x=2
JulijaS [17]

Answer:

33

Step-by-step explanation:

3(7+x^{2}); x=2

=3(7+2^{2})

=3(7+4)

= 33

5 0
2 years ago
If the first differences of a sequence are a constant -7 and the third term is 22, find the first 5 terms of the sequence.
Andru [333]

Answer:

36, 29, 22, 15, 8

Step-by-step explanation:

Step 1: State known information

First difference is -7

Third term of the sequence is 22

Step 2: Find first 5 terms

You just need to add and subtract 7 to 22 and the answer 5 times

1. 36 +7

2. 29 +7

3. 22 <- We know 22 is the 3rd term

4. 15 -7

5. 8 -7

Therefore the first 5 terms of the sequence is 36, 29, 22, 15, 8

8 0
3 years ago
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