Unfortunately, you inadvertently cut off the instructions for this problem when you photographed it. Could you try again, making certain to include the instructions?
Let me guess: perhaps the instructions are 1) determine the slope of the line passing through the given points, or 2) write the equation of the line passing through the given points.
Hey there!!
Parallel lines have the same slope. If they have different slope, then they are not parallel because both lines would combine at some point.
The y-intercept form:
<em>y = mx + b </em>
<u>In this equation, 'm' is considered to be the slope. </u>
The equation we have is 6y = -2x + 4
First, let's divide all the sides with 6 to isolate the value of 'y'.
... 6y = -2x + 4
... y = -1/3x + 2/3
<u><em>The slope is -1/3... </em></u>
<u><em>... hence the slope in the other equation should be -1/3. </em></u>
Equation we got...
... 2y = ax - 5
Let's divide by 2 on both sides...
... y = ax/2 - 5
The slope in this a/2
<u><em>Hence, ... </em></u>
<u><em>... a/2 = -1/3 </em></u>
<u><em>... 3a = -2 </em></u>
<u><em>... a = -2/3 </em></u>
<h2><u><em>
Hence, the value of a is -2/3. </em></u></h2><h3><u><em>
Hope my answer helps!</em></u></h3>
