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Lelechka [254]
4 years ago
13

Based on the chart, determine the identity of a substance that increases in temperature by 11.4oC when 1250J of energy are added

to a 55g sample.
Substance Specific Heat (J/g oC)
Lithium 3.56
Vegetable Oil 1.99
Air 1.02
Iron 0.444
Sand 0.290
Gold 0.129

Salt

Air

Lithium

Vegetable Oil
Chemistry
1 answer:
Firdavs [7]4 years ago
7 0

Answer:

LIthium vegetable oil

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A 0.907 mole sample of ideal gas at 12c occupies a volume of 4.25L. What is the pressure of gas?
mel-nik [20]

Pressure of the ideal gas=505.7kPa

Given:

No of moles=0.907mole

Temperature of the gas=12^{\circ} \mathrm{C}

Volume of the gas=4.25L

To find:

Pressure of the gas

<u>Step by Step Explanation: </u>

Solution:

According to the ideal gas equation

P V=n R T and from this pressure is derived as

P=\frac{n R T}{V}

Where P=Pressure of the gas

V=Volume of the gas=4.25L

n=No of the moles=0.907mole

R=Gas constant=8.314J / m o l^{-1} K^{-1}

T=Temperature of the gas=12^{\circ} \mathrm{C} =273+12=285K

Substitute these known values in the above equation we get

P=\frac{0.907 \times 8.314 \times 285}{4.25}

P=\frac{2149.13}{4.25}

P=505.7kPa

Result:

Thus the pressure of the ideal gas is 505.7kPa

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oksano4ka [1.4K]

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Explanation:

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Units: g/cm^3 or kg/m^3

Aluminum (Al) is one the lightest element and is known to have a density of 2.699 g/cm^3

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